100,000,000+10,000,000+9,000,000+3
Answer:
see below
Step-by-step explanation:
1.5x + 5y = 1152
x = 4y – 2
We can substitute the second equation into the first equation
Which one-variable linear equation can be formed using the substitution method?
1.5(4y-2) +5y = 1152
Distribute
6y -3 +5y = 1152
Combine like terms
11y-3 = 1152
Add 3 to each side
11y-3+3 = 1152+3
11y = 1155
Divide each side by 11
11y/11 = 1155/11
y = 105
How many $5 raffle tickets were sold?
105 5 dollar tickets were sold
Now we need to find the number of 1.50 tickets
Which equation can be used to determine how many $1.50 raffle tickets were sold?
x = 4y – 2
x = 4(105) -2
=420-2
= 418
How many $1.50 raffle tickets were sold?
418 $1.50 tickets were sold
Answer:
A number line going from 0 to 4.5 in increments of 0.5
Step-by-step explanation:
This solution makes the most sense because 4.5 and 2.5 both have a decimal of 0.5
So,
1. Type I profits $20
2. Type II profits $30
3. Type III profits $40
4. I/day < 100
5. Type I needs 5 hrs.
6. Type II needs 10 hrs.
7. Type III needs 15 hrs.
8. Total hrs. available: 2000 hrs.
Every +5 hrs. spent yields an extra $10.
If we use 500 hrs. to make 100 Type I stereos, we will profit $2000.
If we use 500 hrs. to make 50 Type II stereos, we will profit $1500.
If we use 495 hrs. to make 33 Type III stereos, we will profit $1320.
We should use the first 500 hrs. to make Type I stereos.
We should use the last 1500 hrs. to make Type II stereos.
$2000 + $4500 = x
$6500 = x
There must be 100 Type I stereos made along with 150 Type II stereos made.
Answer:
∂u/∂xi = i·cos(sn)
Step-by-step explanation:
For u = sin(v), the partial derivative of u with respect to xi is ...
∂u/∂xi = cos(v)·∂v/xi
In this case, v=sn, and ∂sn/∂xi = i, so the derivatives of interest are ...
∂u/∂xi = i·cos(sn)
