T varies inversely as the square root of u.t = 3 when u = 4.Find t when u = 49.

Mathematics

1 answer:

RoseWind [281]2 years ago

6 0

Answer:

t = $\frac{6}{7}$

Step-by-step explanation:

Given that t varies inversely as the square root of u then the equation relating them is

t = $\frac{k}{\sqrt{u} }$ ← k is the constant of variation

To find k use the condition t = 3 when u = 4, thus

k = t $\sqrt{u}$ = 3 × $\sqrt{4}$ = 3 × 2 = 6

t = $\frac{6}{\sqrt{u} }$ ← equation of variation

When u = 49, then

t = $\frac{6}{\sqrt{49} }$ = $\frac{6}{7}$

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