Answer:
im not really sure but i think its b
Step-by-step explanation:
(a) The probability that there is no open route from A to B is (0.2)^3 = 0.008.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:

(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:

β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:

Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:


Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.
It is 1.5 times because $63 divided by $42 is $1.5.
I hope this is what you meant.
Answer:
it has 1200
Step-by-step explanation:
because 900+300=1200
<span>The pair of integers that I chose are:
(a) sum is –3
5 + (-8) = -3
(b) difference is –5
2 - 7 = -5
(c) difference is 2
14 -12 = 2
(d) sum is 0
2 - 2 = 0</span>