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professor190 [17]
1 year ago
8

Meg used this table to track the average attendance from month to month at her theater for five months. A 5-column table with 1

row is titled Percent Increase and Decrease. Column 1 is labeled October with entry negative 1. Column 2 is labeled November with entry 0.5. Column 3 is labeled December with entry negative 0.9. Column 4 is labeled January with entries three-fourths. Column 5 is labeled February with entry one-half. A number line going from negative 1 to positive 1 in increments of 0.25. Graph the numbers on the number line. Choose the inequality symbol that makes each comparison true. Nov. Feb. Oct. Dec. Jan. Nov.
Mathematics
2 answers:
White raven [17]1 year ago
8 0

Answer:

B - Her monthly average would have increased by $19.57. ... Katie works as a waitress and records her monthly tips in the table shown below. If Katie decided not to work the month of November, how would her five month average compare to her six month ... Lisa is currently taking physics as one of her electives in school.

Step-by-step explanation:

Llana [10]1 year ago
3 0

Answer:

Nov = Feb

Oct< Dec

Jan >Nov

Step-by-step explanation:

i got it right on edge

hope this helps

<3

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-6y + 3(12y) = 20(y - 1) + 15 is it true?
xxMikexx [17]

Answer:

y= - 1/2 (negative half) =  -0.5

Step-by-step explanation:

−6y+3(12y)=20(y−1)+15

Multiply 3 and 12 to get 36.

−6y+36y=20(y−1)+15

Combine −6y and 36y to get 30y.

30y=20(y−1)+15

Use the distributive property to multiply 20 by y−1.

30y=20y−20+15

Add −20 and 15 to get −5.

30y=20y−5

Subtract 20y from both sides.

30y−20y=−5

Combine 30y and −20y to get 10y.

10y=−5

Divide both sides by 10

y= -5/10

Reduce the fraction -5/10 = -0.5 to lowest terms by extracting and cancelling out 5 .

5 0
1 year ago
It is said that a student’s college GPA (grade point index) can be predicted by his/her HOCS (higher- order cognitive skills) su
cricket20 [7]

Answer:

apart from using the hoc to predict the college students gpa, some other variables can be used

1. the students intelligent quotient

2. ability to remember

3. study time

4. gym practice

Step-by-step explanation:

<u>1. the students intelligent quotient</u>

<u>gpa</u><u> </u>has a positive relationship with iq. they are both directly related. The more the iq of a a student, the greater is his ability to understand and have a good gpa. the slope will therefore be positive and be in an upward direction.

2. <u>ability to remember</u>

the gpa of students who have a good ability to remember but do not have a good grasp of the subject may not be high. the slope would be in a slightly upward direction

3. <u>study time</u>

gpa and practice have a positive relationship. the more a student studies, the more likelihood exists of having a better gpa. the slope would be upward bound.

4. <u>gym</u><u> </u><u>practice</u>

gpa and gym practice are not related so the slope would be in a downward direction.

when interpreting the direction of relationship after carrying out such an analysis, it is useful to watch out for the accompanying signs of the variables. if the sign of the beta coefficient is positive then a positive relationship with the dependent variable exists.

6 0
2 years ago
A drawer contains black socks and white socks. 80% of the socks are white socks. A number generator simulates randomly selecting
Zielflug [23.3K]

D is the righr Answer

Hope this Helpful:)

5 0
1 year ago
Read 2 more answers
For which values of a the system has no solution: x≤5, x≥a
soldi70 [24.7K]

Given:

The system of inequalities is

x\leq 5

x\geq a

To find:

The values of a for which the system has no solution.

Solution:

We have,

x\leq 5        ...(1)

It means the value of x is less than or equal to 5.

x\geq a        ...(2)

It means the value of x is greater than or equal to a

Using (1) and (2), we get

a\leq x\leq 5

But if a is great than 5, then there is no value of which satisfies this inequality.

Therefore, the system has no solution for a>5.

7 0
2 years ago
Use the table to answer the question. House A $124,270 Annual appreciation 4% House B $114,270 Annual appreciation 5% In which o
Varvara68 [4.7K]
For the house A we have:
 f (x) = 124270 (1.04) ^ x
 Evaluating for 7, 8, 9 and 10 we have:
 f (7) = 124270 (1.04) ^ 7 = 163530.8422
 f (8) = 124270 (1.04) ^ 8 = 170072.0759
 f (9) = 124270 (1.04) ^ 9 = 176874.9589
 f (10) = 124270 (1.04) ^ 10 = 183949.9573

 For house B we have:
 
f (x) = 114270 (1.05) ^ x
 Evaluating for 7, 8, 9 and 10 we have:
 f (7) = 114270 (1.05) ^ 7 = 160789.3653
 f (8) = 114270 (1.05) ^ 8 = 168828.8336
 f (9) = 114270 (1.05) ^ 9 = 177270.2752
 f (10) = 114270 (1.05) ^ 10 = 186133.789

 We observe that for years 7 and 8 the value of house A is greater than the value of house B.

 Answer:
 
7 and 8
4 0
1 year ago
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