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professor190 [17]
1 year ago
8

Meg used this table to track the average attendance from month to month at her theater for five months. A 5-column table with 1

row is titled Percent Increase and Decrease. Column 1 is labeled October with entry negative 1. Column 2 is labeled November with entry 0.5. Column 3 is labeled December with entry negative 0.9. Column 4 is labeled January with entries three-fourths. Column 5 is labeled February with entry one-half. A number line going from negative 1 to positive 1 in increments of 0.25. Graph the numbers on the number line. Choose the inequality symbol that makes each comparison true. Nov. Feb. Oct. Dec. Jan. Nov.
Mathematics
2 answers:
White raven [17]1 year ago
8 0

Answer:

B - Her monthly average would have increased by $19.57. ... Katie works as a waitress and records her monthly tips in the table shown below. If Katie decided not to work the month of November, how would her five month average compare to her six month ... Lisa is currently taking physics as one of her electives in school.

Step-by-step explanation:

Llana [10]1 year ago
3 0

Answer:

Nov = Feb

Oct< Dec

Jan >Nov

Step-by-step explanation:

i got it right on edge

hope this helps

<3

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Enzo is studying the black bear population at a large national park.
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Answer:

2,973

Step-by-step explanation:

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B(t) = 2500 \cdot 2^{0.01t}

Where t is the time(in years) elapsed since the beginning of the study.

We want to determine the black bear population in 25 years time, t=25.

B(25) = 2500 \cdot 2^{0.01*25}\\=2973.02\\\approx 2973

There will be 2,973 black bears in 25 years time.

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73/12 or 6 1/12 hours more than before
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1 year ago
In electrical engineering, the unwanted "noise" in voltage or current signals is often modeled by a Gaussian (i.e., normal) dist
vladimir1956 [14]

Answer:

Cov(X, Y) =0.029.

Step-by-step explanation:

Given that :

The noise in a particular voltage signal has a constant mean of 0.9 V. that is μ = 0.9V ............(1)

Also, the two noise instances sampled τ seconds apart have a bivariate normal distribution with covariance.

0.04e–jτj/10 ............(2)

Having X and Y denoting the noise at times 3 s and 8 s, respectively, the difference of time = 8-3 = 5seconds.

That is, they are 5 seconds apart,

τ = 5 seconds..............(3)

Thus,

Cov(X, Y), for τ = 5seconds = 0.04e-5/10

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5 0
1 year ago
Based on this data, what is a reasonable estimate of the probability that Nate scores 8-11 points next basketball game? Experime
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Answer:

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Step-by-step explanation:

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1 year ago
Which of the number(s) below are potential roots of the function? p(x) = x4 + 22x2 – 16x – 12
Neporo4naja [7]

Complete question is;

Which of the number(s) below are potential roots of the function? p(x) = x⁴ + 22x² – 16x – 12

A) ±6

B) ±1

C) ±3

D) ±8

Answer:

Options A, B & C: ±6, ±1, ±3

Step-by-step explanation:

We are given the polynomial;

p(x) = x⁴ + 22x² – 16x – 12

Now, the potential roots will be all the rational numbers equivalent of p/q.

Where;

p are the factors of the constant term of the polynomial

q are the factors of the leading coefficient of the polynomial

Now, in the given polynomial, the constant term is seen as -12 while leading coefficient is 1 which is the coefficient of x⁴.

We know that factors of 12 are any of:

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Thus, all the potential roots of the polynomial function are;

±1, ±2, ±3, ±4, ±6 and ±12

From the options given, option A, B & C could be the potential roots.

6 0
1 year ago
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