Metro buses are scheduled to arrive at each stop every 30 minutes. If the time a person waits at a bus stop is uniformly distrib
1 answer:
Answer:
The probability is
Step-by-step explanation:
From the question we are told that
The maximum wait is
The minimum wait would be
Generally the probability that you will wait more than 25 minutes for a bus is mathematically represented as
Now given that the time a person waits is uniformly distributed and that the maximum is 30 then we can evaluate the above probability as
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Answer:
46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups
Step-by-step explanation:
We use two binomial trials to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
Probability of at least nine participants finishing the study in a group.
0.2 probability of a students dropping out. So 1 - 0.2 = 0.8 probability of a student finishing the study. This means that .
10 students, so
We have to find:
Then
0.3758 probability that at least nine participants complete the study in a group.
Calculate the probability that at least nine participants complete the study in one of the two groups, but not in both groups?
0.3758 probability that at least nine participants complete the study in a group. This means that
Two groups, so
We have to find P(X = 1).
46.91% probability that at least nine participants complete the study in one of the two groups, but not in both groups