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Lapatulllka [165]
2 years ago
15

Joanna set a goal to drink more water daily. The number of ounces of water she drank each of the last seven days is shown below.

60, 58, 64, 64, 68, 50, 57. On the eighth day, she drinks 82 ounces of water. Select all the true statements about the effect of the eighth day's amount on Joanna's daily amount distribution. The average daily amount of water is the same with or without the inclusion of the eighth day's amount. The median amount of water is the same with or without the inclusion of the eighth day's amount. The interquartile range of the data decreases when the eighth day's amount is included in the data. The interquartile range of the data increases when the eighth day's amount is included in the data. The median amount of water is higher when the eighth day's amount is included in the data.
Mathematics
2 answers:
butalik [34]2 years ago
8 0
(a) Data with the eight day's measurement.
Raw data:      [60,58,64,64,68,50,57,82], 
Sorted data:  [50,57,58,60,64,64,68,82]
Sample size = 8 (even)
mean            = 62.875
median         = (60+64)/2 = 62
1st quartile   = (57+58)/2 = 57.5
3rd quartile  = (64+68)/2 =  66
IQR = 66 - 57.5 = 8.5

(b) Data without the eight day's measurement.
Raw data:      [60,58,64,64,68,50,57]
Sorted data:  [50,57,58,60,64,64,68]
Sample size = 7 (odd)
mean            = 60.143
median         = 60
1st quartile   = 57
3rd quartile = 64
IQR = 64 -57 = 7

Answers:
1. The average is the same with or without the 8th day's data.  FALSE
2. The median is the same with or without the 8th day's data.  FALSE
3. The IQR decreases when the 8th day is included.                  FALSE
4. The IQR increases when the 8th day is included.                   TRUE
5. The median is higher when the 8th day is included.              TRUE

gogolik [260]2 years ago
3 0

Answer:The interquartile range of the data increases when the eighth day's amount is included in the data.

The median amount of water is higher when the eighth day's amount is included in the data.

Step-by-step explanation: right on plato

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liraira [26]

Answer:

<u>The drama club ordered 150 short-sleeved shirts and 100 long-sleeved shirts</u>

Step-by-step explanation:

1. Let's review all the information provided for answering the questions properly:

5x + 10y = 1,750

1/3x + 1/2y = 100

x = number of short-sleeved shirts ordered

y = number of long-sleeved shirts ordered

Resolving the 1st equation:

5x + 10y = 1,750

5x = 1,750 - 10y

x = 350 - 2y (Dividing by 5 at both sides)

Resolving  the 2nd equation:

1/3x + 1/2y = 100

1/3 (350 - 2y) + 1/2y = 100

350/3 -2y/3 + 1/2y = 100

700 - 4y + 3y = 600 (Lowest common denominator = 6)

-y = 600 - 700 (Subtracting 700 at both sides)

<u>y = 100</u> (Dividing by - 1)

Finding the value of x in the 1st equation:

5x + 10 (100) = 1,750

5x + 1,000 = 1,750

5x = 1,750 - 1,000 (Subtracting 1,000 at both sides)

5x = 750

<u>x = 150</u> (Dividing by 5)

2. Proving that x = 150 and y = 100 are correct

1/3x + 1/2y = 100

1/3 * 150 + 1/2 * 100 = 100

150/3 + 100/2 = 100

50 + 50 = 100

100 = 100

<u>We proved that x = 150 and y = 100 are correct</u>

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2 years ago
Salmon often jump waterfalls to reach their breeding grounds. One salmon starts 2.00m from a waterfall that is 0.55m tall and ju
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Answer: 6.2 m/s

Explanation:

1) This is a projectile motion (parabolic)

2) Velocity:

i) initial velocity = V₀

ii) Horizontal component:

V₀x = V₀ cos α

The horizontal velocity is constant, so Vx = V₀x

ii) Vertical component:

V₀y = V₀ sin α

The vertical component is linear with acceleration = g ≈ 9.8 m/s²

Vy = V₀y - gt = V₀ sin α - gt

3) Displacement equations

i) Horizontal displacment:

x = V₀ cosα t

ii) Vertical displacement:

y = V₀ sin α t - g t² / 2

y ≈ V₀ sin α t - 4.9 t²

4) Solution

i) x = V₀ cosα t = V₀ cos(32°) t = 2.00 m ← salmon starts 2.00m from a waterfall

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iii) Replace V₀ with 2 / [cos(32°) t ]

y = sin(32°) × 2 / [cos(32°) t ] × t - 4.9t² = 2 tan(32°) - 4.9t²

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V₀ = 2 / [cos(32°) (0.38) ] = 6.2 m/s

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antoniya [11.8K]
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Answer: 25

Step-by-step explanation:

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We reduce the nice fraction to its lowest term.

8/200 = 1/25

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2 years ago
Make y the subject of the formula x=a-2by squared
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Answer:

y = ± \sqrt{\frac{a-x}{2b} }

Step-by-step explanation:

Given

x = a - 2by² ( subtract a from both sides )

x - a = - 2by² ( multiply through by - 1 to clear the leading negative )

a - x = 2by² ( divide both sides by 2b )

\frac{a-x}{2b} = y² ( take the square root of both sides )

y = ± \sqrt{\frac{a-x}{2b} }

7 0
2 years ago
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