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Lapatulllka [165]
2 years ago
15

Joanna set a goal to drink more water daily. The number of ounces of water she drank each of the last seven days is shown below.

60, 58, 64, 64, 68, 50, 57. On the eighth day, she drinks 82 ounces of water. Select all the true statements about the effect of the eighth day's amount on Joanna's daily amount distribution. The average daily amount of water is the same with or without the inclusion of the eighth day's amount. The median amount of water is the same with or without the inclusion of the eighth day's amount. The interquartile range of the data decreases when the eighth day's amount is included in the data. The interquartile range of the data increases when the eighth day's amount is included in the data. The median amount of water is higher when the eighth day's amount is included in the data.
Mathematics
2 answers:
butalik [34]2 years ago
8 0
(a) Data with the eight day's measurement.
Raw data:      [60,58,64,64,68,50,57,82], 
Sorted data:  [50,57,58,60,64,64,68,82]
Sample size = 8 (even)
mean            = 62.875
median         = (60+64)/2 = 62
1st quartile   = (57+58)/2 = 57.5
3rd quartile  = (64+68)/2 =  66
IQR = 66 - 57.5 = 8.5

(b) Data without the eight day's measurement.
Raw data:      [60,58,64,64,68,50,57]
Sorted data:  [50,57,58,60,64,64,68]
Sample size = 7 (odd)
mean            = 60.143
median         = 60
1st quartile   = 57
3rd quartile = 64
IQR = 64 -57 = 7

Answers:
1. The average is the same with or without the 8th day's data.  FALSE
2. The median is the same with or without the 8th day's data.  FALSE
3. The IQR decreases when the 8th day is included.                  FALSE
4. The IQR increases when the 8th day is included.                   TRUE
5. The median is higher when the 8th day is included.              TRUE

gogolik [260]2 years ago
3 0

Answer:The interquartile range of the data increases when the eighth day's amount is included in the data.

The median amount of water is higher when the eighth day's amount is included in the data.

Step-by-step explanation: right on plato

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Which statement describes a process to solve sqrt b+20 - sqrt b=5?
babunello [35]

Answer:

Step-by-step explanation:

The equation is:

√b+20 - √b = 5

The first step is we will add √b to both sides:

√b+20 -√b +√b = 5 +√b

√b+20 = 5+√b

Now take square at both sides:

(√b+20)^2 = (5+√b)^2

b+20 = 25+10√b+b

Now combine the like terms:

b+20-25-b=10√b

-5 = 10√b

Divide both the terms by 10

-5/10 = 10√b/10

-1/2=√b

Take square at both sides:

(-1/2)^2 = (√b)^2

1/4 = b

So in this type of question we add radical terms to both sides and square both sides twice....

7 0
1 year ago
You and a friend each have a collection of tokens. Initially, for every 8 tokens you had, your friend had 3. After you give half
Sonbull [250]

Answer: 30 token

Step-by-step explanation:

Since, according to the question,

Initially, for every 8 tokens I had, my friend had 3.

Therefore, ratio of tokens that me and my friend is  8 : 3

Let I have 8 x tokens and my friend has 3 x tokens, where x is any number.

Then again according to the question,

After I gave half of your friend, my friend now has 18 more tokens than you.

That is, (3x + 4x) - 4x = 18

⇒ 7x - 4x = 18

⇒ 3x = 18

⇒ x = 6

Therefore , Initially the difference between me and my friend's token = 8 x - 3 x = 5 x = 5 × 6 = 30


6 0
2 years ago
Kojo wants to be an author. To improve his writing skills, every day after school he writes 3 pages of a story he is working on.
juin [17]

Kojo has been writing for 27 days, 3 x 27 = 81.

3 0
1 year ago
Mick completes a total of 5 assessments for his course. He gets these marks 56,42,47,59,48. Mike needs an average mark of 50 or
Mars2501 [29]
To find the average assessment, add the 5 grades together, then divide by the quantity of grades added together (in this case 5).

=56 + 42 + 47 + 59 + 48
=252

=252 ÷ 5
=50.4 average

ANSWER: Yes, he passes his course with an average grade of 50.4.

Hope this helps! :)
4 0
2 years ago
The number of rainbow smelt in Lake Michigan had an average rate of change of −19.76 per year between 1990 and 2000. The bloater
mojhsa [17]
Let x =  number of years between 1990 and  2000.

Rainbow smelt:
Initial population = 227
Average yearly rate of change = -19.76
The linear function that models the population is
y₁ = 227 - 19.76x

Bloater fish
Initial population = 1052
Average yearly rate of change = -92.57
The linear function that models the population is
y₂ = 1052 - 92.57x

When the two populations are equal, then y₁ = y₂.
That is
227 - 19.76x = 1052 - 92.57x
(92.57 - 19.76)x = 1052 - 227
72.81x = 825
x = 11.33 years
   = 11 years, 0.33*12 months
   = 11 years, 4 months
Add x to 1990 to obtain the year April 2011.

Answer:
x = 11.33 years.
This occurs in April 2001.
5 0
2 years ago
Read 2 more answers
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