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Lapatulllka [165]
2 years ago
15

Joanna set a goal to drink more water daily. The number of ounces of water she drank each of the last seven days is shown below.

60, 58, 64, 64, 68, 50, 57. On the eighth day, she drinks 82 ounces of water. Select all the true statements about the effect of the eighth day's amount on Joanna's daily amount distribution. The average daily amount of water is the same with or without the inclusion of the eighth day's amount. The median amount of water is the same with or without the inclusion of the eighth day's amount. The interquartile range of the data decreases when the eighth day's amount is included in the data. The interquartile range of the data increases when the eighth day's amount is included in the data. The median amount of water is higher when the eighth day's amount is included in the data.
Mathematics
2 answers:
butalik [34]2 years ago
8 0
(a) Data with the eight day's measurement.
Raw data:      [60,58,64,64,68,50,57,82], 
Sorted data:  [50,57,58,60,64,64,68,82]
Sample size = 8 (even)
mean            = 62.875
median         = (60+64)/2 = 62
1st quartile   = (57+58)/2 = 57.5
3rd quartile  = (64+68)/2 =  66
IQR = 66 - 57.5 = 8.5

(b) Data without the eight day's measurement.
Raw data:      [60,58,64,64,68,50,57]
Sorted data:  [50,57,58,60,64,64,68]
Sample size = 7 (odd)
mean            = 60.143
median         = 60
1st quartile   = 57
3rd quartile = 64
IQR = 64 -57 = 7

Answers:
1. The average is the same with or without the 8th day's data.  FALSE
2. The median is the same with or without the 8th day's data.  FALSE
3. The IQR decreases when the 8th day is included.                  FALSE
4. The IQR increases when the 8th day is included.                   TRUE
5. The median is higher when the 8th day is included.              TRUE

gogolik [260]2 years ago
3 0

Answer:The interquartile range of the data increases when the eighth day's amount is included in the data.

The median amount of water is higher when the eighth day's amount is included in the data.

Step-by-step explanation: right on plato

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What is the standard deviation of the market portfolio if the standard deviation of a fully diversified portfolio with a beta of
Nina [5.8K]

Answer:

22.5%

Step-by-step explanation:

let the standard deviation for market portfolio = σₙ

Also let the standard deviation for fully diversified portfolio = σₓ

<u>To calculate fully diversified portfolio</u>

fully diversified portfolio has <em>σₓ = βσₙ</em>

From the given question beta (β) = 1.25

Also standard deviation for market portfolio (σₙ)  = 18% = 0.18

<em>From the equation above,  σₓ = βσₙ </em>= 1.25×0.18 = 0.225

                                                             = 22.5% (converting to percentage)

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-6,-2,0,1,3/2 whats the sequence and what do I multiply by
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The lifetime of a cheap light bulb is an exponential random variable with mean 36 hours. Suppose that 16 light bulbs are tested
photoshop1234 [79]

Answer:

P(T

Step-by-step explanation:

Previous concepts

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}, x>0

And 0 for other case. Let X the random variable that represent "The number of years a radio functions" and we know that the distribution is given by:

X \sim Exp(\lambda=\frac{1}{16})

Or equivalently:

X \sim Exp(\mu=16)

Solution to the problem

For this case we are interested in the total T, and we can find the mean and deviation for this like this:

\bar X =\frac{\sum_{i=1}^n X_i}{n}=\frac{T}{n}

If we solve for T we got:

T= n\bar X

And the expected value is given by:

E(T) = n E(\bar X)= n \mu= 16*36=576

And we can find the variance like this:

Var(T) = Var(n\bar X)=n^2 Var(\bar X)= n^2 *\frac{\sigma^2}{n}=n \sigma^2

And then the deviation is given by:

Sd(T)= \sqrt{n} \sigma=\sqrt{16} *36=144

And the distribution for the total is:

T\sim N(n\mu, \sqrt{n}\sigma)

And we want to find this probability:

P(T< 600)

And we can use the z score formula given by:

z=\frac{T- \mu_T}{\sigma_T}

And replacing we got this:

P(T

6 0
2 years ago
In 2004, a magazine's circulation was about 1,000,000 readers. In 2014, the magazine had about 2,000,000 readers. Write a linear
professor190 [17]

Answer:

r(t)=100,000t+600,000

Step-by-step explanation:

Let

r ----> the number of readers (y-coordinate or dependent variable)

t ----> the number of years after 2000 (x-coordinate or independent variable)

Remember

2004 ----> represent t=4 years

2014 ----> represent t=14 years

we have the ordered pairs

(4,1,000,000) and (14,2,000,000)

step 1

Find the slope

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values

m=\frac{2,000,000-1,000,000}{14-4}

m=\frac{1,000,000}{10}

m=100,000\frac{readers}{year}

step 2

Find the equation of the line in point slope form

r-r1=m(t-t1)

we have

m=100,000\\point\ (4,1,000,000)

substitute

r-1,000,000=100,000(t-4)

step 3

Convert to slope intercept form

r=mt+b

isolate the variable r

r-1,000,000=100,000t-400,000\\r=100,000t-400,000+1,000,000\\r=100,000t+600,000

step 4

Convert to function notation

r(t)=100,000t+600,000

6 0
2 years ago
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