Answer: $14.0
Step-by-step explanation:
For us to calculate this question, we have to find 20% of $17.45 and then subtract the value gotten from $17.45. This will be:
= $17.45 - (20% × $17.45)
= $17.45 - (0.2 × $17.45)
= $17.45 - $3.49
= $13.96
= $14.0 to nearest cent
Answer:
0.14 s
Step-by-step explanation:
s = -2.7 t² + 40t + 6.5
Let s = 12
12 = -2.7t² + 40t + 6.5 Subtract 12 from each side
-2.7t² + 40t + 6.5 - 12 = 0
-2.7t² + 40t - 5.5 = 0
Apply the <em>quadratic formula
</em>

a = -2.7; b = 40; c = -5.5




x = 7.41 ± 7.27
x₁ = 0.14; x₂ = 14.68
The graph below shows the roots at x₁ = 0.134 and x₂ = 14.68.
The Moon’s surface is at -12 ft. The ball will be 12 ft above the Moon’s surface (crossing the x-axis) in 0.14 s.
The second root gives the time the ball will be 12 ft above the Moon’s surface on its way back down.
Answer:
option C. Angle BTZ Is-congruent-to Angle BUZ
Step-by-step explanation:
Point Z is equidistant from the vertices of triangle T U V
So, ZT = ZU = ZV
When ZT = ZU ∴ ΔZTU is an isosceles triangle ⇒ ∠TUZ=∠UTZ
When ZT = ZV ∴ ΔZTV is an isosceles triangle ⇒ ∠ZTV=∠ZVT
When ZU = ZV ∴ ΔZUV is an isosceles triangle ⇒ ∠ZUV=∠ZVU
From the figure ∠BTZ is the same as ∠UTZ
And ∠BUZ is the same as ∠TUZ
So, the statement that must be true is option C
C.Angle BTZ Is-congruent-to Angle BUZ
Answer:
<u>0.9524</u>
Step-by-step explanation:
<em>Note enough information is given in this problem. I will do a similar problem like this. The problem is:</em>
<em>The Probability of a train arriving on time and leaving on time is 0.8.The probability of the same train arriving on time is 0.84. The probability of the same train leaving on time is 0.86.Given the train arrived on time, what is the probability it will leave on time?</em>
<em />
<u>Solution:</u>
This is conditional probability.
Given:
- Probability train arrive on time and leave on time = 0.8
-
Probability train arrive on time = 0.84
-
Probability train leave on time = 0.86
Now, according to conditional probability formula, we can write:
= P(arrive ∩ leave) / P(arrive)
Arrive ∩ leave means probability of arriving AND leaving on time, that is given as "0.8"
and
P(arrive) means probability arriving on time given as 0.84, so:
0.8/0.84 = <u>0.9524</u>
<u></u>
<u>This is the answer.</u>