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Afina-wow [57]
2 years ago
9

Possible values for the area A of the rectangle shown are 12 ≤ A ≤ 36. Write and solve a compound inequality to find the possibl

e values of x. Are these values all viable in this situation?I really need help
Mathematics
1 answer:
Aleks04 [339]2 years ago
6 0

Answer:

x can take any value and are viable in this situation if and only if it is a positive number

Step-by-step explanation:

We know that the area of a rectangle is given by:

A = x * y

So if we replace we have:

12 ≤ x * y ≤ 36

We divide by y, and we have:

12 / y ≤ x ≤ 36 / y

Which means that the value of x depends on y, that is to say if y is worth 1, the inequality would be:

 12 ≤ x ≤ 36

In the event that y is equal to 2:

 12/2 ≤ x ≤ 36/2

 6 ≤ x ≤ 18

Which means, that depending on y, x can take any value and are viable in this situation if and only if it is a positive number.

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A stadium has two sponsorship deals. Deal A had revenue of $100,000 and expense of $10,000. Deal B has revenue of $50,000 and ex
horsena [70]

Answer:

Deal A) 90% Profit ; Deal B) 60% Profit

Step-by-step explanation:

Multiple ways of solving this problem here is one way:

100k-10k = 90k(Revenue) : Then you make this as a percent by 100k then multiply it by 100.

100*((100,000-10,000)/100,000) = 90%

The same is true for the other equation:

100*((50,000-20,000)/50,000) = 60%


4 0
2 years ago
Read 2 more answers
How far should Galileo walk up the inclined plane?
sergejj [24]

Answer:

Step-by-step explanation:

150/x=sin 15

x=150/sin 15 ≈579.56 m

4 0
2 years ago
A particle travels 24.6 km in 30 minutes. Find the
tatyana61 [14]

Answer:

See the solutions below

Step-by-step explanation:

Given data

Distance = 24.6km

in meters= 24.6*1000= 24600m

time= 30 minutes

in seconds= 30*60= 1800

int hours= 0.5 hour

speed of the particle in

(i) km/h= 24.6/0.5= 49.2 km/h

(ii) m/s.= 24600/ 1800= 13.66 m/s

8 0
1 year ago
Triangle A B C is reflected across line m to form triangle A prime B prime C prime. Triangle A prime B prime C prime is rotated
Helga [31]

Answer:

  1. reflection across line m
  2. rotation about point A'

Step-by-step explanation:

The problem statement tells you exactly what the transformations are.

The first transformation is reflection across line m.

The second transformation is rotation about point A'.

_____

These are both rigid transformations, so ΔABC ≅ A'B''C''.

6 0
2 years ago
Find the average value of the function f(x, y, z) = 5x2z 5y2z over the region enclosed by the paraboloid z = 4 − x2 − y2 and the
S_A_V [24]
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin. 

<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>

<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>

<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>

<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>


<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>

<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>

<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>

<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>

<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
3 0
2 years ago
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