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Afina-wow [57]
2 years ago
9

Possible values for the area A of the rectangle shown are 12 ≤ A ≤ 36. Write and solve a compound inequality to find the possibl

e values of x. Are these values all viable in this situation?I really need help
Mathematics
1 answer:
Aleks04 [339]2 years ago
6 0

Answer:

x can take any value and are viable in this situation if and only if it is a positive number

Step-by-step explanation:

We know that the area of a rectangle is given by:

A = x * y

So if we replace we have:

12 ≤ x * y ≤ 36

We divide by y, and we have:

12 / y ≤ x ≤ 36 / y

Which means that the value of x depends on y, that is to say if y is worth 1, the inequality would be:

 12 ≤ x ≤ 36

In the event that y is equal to 2:

 12/2 ≤ x ≤ 36/2

 6 ≤ x ≤ 18

Which means, that depending on y, x can take any value and are viable in this situation if and only if it is a positive number.

You might be interested in
The sum of the interior angles of a polygon is
Crank

Answer:

D) 15

Step-by-step explanation:

The sum of the interior angles of a polygon is given by

(n - 2) \times 180

We have that, the sum of the interior angles of a polygon is

26 right angles. We want to find n, the number of sides.

We substitute into the formula to get:

(n - 2) \times 180 = 26 \times 90

Divide through by 90

2(n - 2) = 26

Divide through by 2

n - 2 = 13

n = 13 + 2

n = 15

6 0
2 years ago
Given: FGKL is a trapezoid, m∠F=90°, m∠K=120°, FK=LK=a Find: The length of midsegment.
lisov135 [29]

Try this solution (note, the length of midsegment is (KG+FL)/2), all the details are in the attachment.

Answer is marked with green colour.

7 0
2 years ago
A pipe of diameter 64mm discharges water at a rate of 2.05mm/s into an empty cylindrical tank of diameter 7.6cm and height 2.3m.
inessss [21]

Answer:

Diameter of pipe = D = 64mm

cross sectional Area of pipe= A = pi * (D/2)^2 = pi * (32)^2 = 1024pi  mm^2

Discharge Rate of water = v = 2.05 mm/s

Volume of Cylinder = V = pi * (D/2)^2 * h = pi * (38)^2 * 2300 = 3321200pi  mm^3

(Area of pipe)*(Rate) = (Volume) / (Time)

Time = T = (Volume) / [(Area of pipe)*(Rate)]

              = (3321200pi)/(1024pi * 2.05)

              = 1582.126524s

4 0
2 years ago
Wheel A has a diameter of 25.4 inches. Wheel B has a diameter of 22.5 inches. About how much farther will Wheel A travel in one
MissTica

Wheel A will travel a distance of approximately 9 in more than wheel B in one rotation.

<u>Explanation:</u>

Given:

Diameter of wheel A, d₁ = 25.4 in

Radius of wheel A, r₁ = 12.7 in

Diameter of wheel B = 22.5 in

Radius of Wheel B, d₂ = 11.25 in

Distance travelled by A = ?

In one rotation, the distance travelled by a wheel is equal to its circumference.

Circumference of a wheel = 2πr

Circumference of wheel A = 2πr₁

                                            = 2 X 3.14 X 12.7 in

                                            = 80 in

Circumference of wheel B = 2πr₂

                                              = 2 X 3.14 X 11.25 in

                                              = 71 in

Therefore, wheel A will travel a distance of approximately 9 (80 - 71 in) in more than wheel B in one rotation.

3 0
2 years ago
For Joe's illness, the doctor gave him a prescription of 28 pills. He needs to take 4 pills the first day, and then 2 pills each
kiruha [24]

Answer:

12 days.

Step-by-step explanation:

I looked at it this way:

He has to take 4/28 pills the first day, so it's 28-4=24. Then I divided 24 by 2.

In simpler terms:

28-4=24

24/2

12

8 0
2 years ago
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