Question

What is the equation of this line? y=12x−3 y=−12x−3 y=−2x−3 y=2x−3 Number graph ranging from negative 5 to 5 on both the x and y axis. A line passes through the point begin ordered pair 0 comma negative 3 end ordered pair and the point begin ordered pair 4 comma negative 1 end ordered pair

Answer 1

We are given that

A line passes through two  points as

(0,-3)  and (4,-1)

$(x_1,y_1)=(0,-3)$

$x_1=0,y_1=-3$

$(x_2,y_2)=(4,-1)$

$x_2=4,y_2=-1$

Firstly, we can find slope

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{-1+3}{4-0}$

$m=\frac{2}{4}$

$m=\frac{1}{2}$

now, we can use point  slope form of line

$y-y_1=m(x-x_1)$

we can plug values

$y+3=\frac{1}{2} (x-0)$

$y+3=\frac{1}{2}x$

$y=\frac{1}{2}x-3$

so, the equation of line is

$y=\frac{1}{2}x-3$...............Answer

Answer 2

Answer:

y = -2/3x +2

Step-by-step explanation: