Ask question

Ask question

All categories

svet-max [94.6K]

2 years ago

10

What is the equation of this line? y=12x−3 y=−12x−3 y=−2x−3 y=2x−3 Number graph ranging from negative 5 to 5 on both the x and y

axis. A line passes through the point begin ordered pair 0 comma negative 3 end ordered pair and the point begin ordered pair 4 comma negative 1 end ordered pair

2 answers:

Tems11 [23]2 years ago

5 0

We are given that

A line passes through two points as

(0,-3) and (4,-1)

$(x_1,y_1)=(0,-3)$

$x_1=0,y_1=-3$

$(x_2,y_2)=(4,-1)$

$x_2=4,y_2=-1$

Firstly, we can find slope

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{-1+3}{4-0}$

$m=\frac{2}{4}$

$m=\frac{1}{2}$

now, we can use point slope form of line

$y-y_1=m(x-x_1)$

we can plug values

$y+3=\frac{1}{2} (x-0)$

$y+3=\frac{1}{2}x$

$y=\frac{1}{2}x-3$

so, the equation of line is

$y=\frac{1}{2}x-3$ ...............Answer

algol [13]2 years ago

5 0

Answer:

y = -2/3x +2

Step-by-step explanation:

You might be interested in

According to a Los Angeles Times study of more than 1 million medical dispatches from 2007 to 2012, the 911 response time for me

Reil [10]

Answer:

a) $\bar X=10.65$

$Median =\frac{10.7+10.7}{2}=10.7$

$Mode= 10.7$

b) $Range = 11.8-8.3=3.5$

$s= 0.948$

c) $IQR = Q_3 -Q_1 = 11.05-10.55=0.5$

And we can find the usual limits with:

$Lower = Q_1 -1.5 IQR = 10.55 -1.5*0.5=9.8$

$Upperer = Q_3 +1.5 IQR = 10.55 +1.5*0.5=11.3$

And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.

d) The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.

And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.

Step-by-step explanation:

We have the following data:

11.8 10.3 10.7 10.6 11.5 8.3 10.5 10.9 10.7 11.2

Part a

We can calculate the sample mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got: $\bar X=10.65$

For the median we need to sort the values on increasing order and we have:

8.3 10.3 10.5 10.6 10.7 10.7 10.9 11.2 11.5 11.8

Since n =10 we can calculate the median as the average between the 5th and 6th position of the dataset ordered and we got:

$Median =\frac{10.7+10.7}{2}=10.7$

The mode would be the most repeated value on this case:

$Mode= 10.7$

Part b

The range is defined as $Range =Max-Min$ and if we replace we got:

$Range = 11.8-8.3=3.5$

We can calculate the standard deviation with the following formula:

$s= sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And if we replace we got:

$s= 0.948$

Part c

For this case we can use the IQR method in order to determine if 8.3 is an outlier or not.

We can calculate the first quartile with these values: 8.3 10.3 10.5 10.6 10.7 10.7 and $Q_1= \frac{10.6+10.7}{2}=10.55$

And for the Q3 we can use: 10.7 10.7 10.9 11.2 11.5 11.8 and we got $Q_3 = \frac{10.9+11.2}{2}=11.05$

Then we can find the IQR like this:

$IQR = Q_3 -Q_1 = 11.05-10.55=0.5$

And we can find the usual limits with:

$Lower = Q_1 -1.5 IQR = 10.55 -1.5*0.5=9.8$

$Upperer = Q_3 +1.5 IQR = 10.55 +1.5*0.5=11.3$

And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.

Part d

The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.

And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.

6 0

2 years ago

John Simone is buying a used car for a total cost of $11,805.00. He’s making a down payment of $1,500.00 and borrowing the remai

VLD [36.1K]

1,500+343(3×12)=13,848
1,500+343(36)=13,848
1500+12,348= 13,848

4 0

2 years ago

Read 2 more answers

Hank invested a total of $20,000, part at 7% and part at 10%. How much did he invest at each rate if the total interest earned i

jolli1 [7]

Answer:

The amount invested at 7% is $12,000 while the amount invested at 10% is $8,000

Step-by-step explanation:

The given parameters are;

The total amount Hank invested = $20,000

The interest earned in one year = $1640

Hank invested part of the $20,000 at 7% interest and part of the $20,000 at 10%

Let the part invested at 7% = X and the part invested at 10% = Y, we have;

7% of X + 10% of Y = $1640 which gives;

0.07×X + 0.1×Y = $1640.....................(1)

X + Y = $20,000.................................(2)

Multiply equation (1) by 10 and subtract equation (1) from equation (2) to get;

X + Y - 10×(0.07×X + 0.1×Y) = $20,000 - 10×$1640

X - 0.7·X - Y - Y = $20,000 - $16,400 = $3,600

0.3·X = $3,600

X = $3,600/0.3 = $12,000

X = $12,000

Y = $20,000 - X = $20,000 - $12,000 = $8,000

Y = $8,000

Therefore, the amount invested at 7% = $12,000 and the amount invested at 10% = $8,000.

7 0

2 years ago

Read 2 more answers

Maggie brought $10 to the candy store she will buy a certain amount of fudge 1 pound cost to 2.30 if p represents the money magg

xxTIMURxx [149]

Question is Incomplete. Complete question is given below;

Maggie brought $10 to the candy store. She will buy a certain amount of fudge. One pound of fudge costs $2.30. If p represents the amount of fudge, in pounds, Maggie buys, which expression represents the money Maggie has left after visiting the candy store?

Answer:

The expression that represent the money Maggie has left after visiting the candy store is $(10-2.3p)$

Step-by-step explanation:

Given:

Money Maggie brought at store = $10

Cost of 1 pound of fudge = $2.30

Let the amount of fudge be p

We need to find the amount of Money Maggie has left with after visiting the store.

The amount of Money Maggie has left with can be calculate by subtracting the amount of fudge she bought multiplied by Cost of 1 pound of fudge with Money Maggie brought at store.

The equation can be framed as;

Money left = $10-2.3p$

Hence, The expression that represent the money Maggie has left after visiting the candy store is $(10-2.3p)$

3 0

2 years ago

An aquarium with a square base has no top. There is a metal frame. Glass costs 5 dollars/m2 and the frame costs 2 dollars/m. The

adell [148]

Answer:

C = 420/h + 400

Step-by-step explanation:

Let s be the side of the square base.

Let h be the height

Volume = s*h

20 = s*h

s = 20/h

Cost of glass is

5(20/h) + 5(4* h*20/h)

= 100/h + 400

Cost of frame is

2*4(20/h) + 2*4(20/h)

= 160/h + 160/h

= 320/h

Total cost = C

C = cost of glass + cost of frame

C = 100/h + 400 + 320/h

C = 420/h + 400

3 0

2 years ago