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Dominik [7]
2 years ago
6

A rancher owns a rectangular piece of land that is 4.1 mi long and 2.5 mi wide. Find the units for the perimeter of the rectangl

e defined by this ranch
Mathematics
2 answers:
Naddik [55]2 years ago
8 0

Answer:

13.1mi

Step-by-step explanation:

Length(l) = 4.1mi

Breadth(b) = 2.5 mi

Perimeter of a rectangle = addition of all sides that is = l + l + b + b as a rectangle has 2 opposite equal length and also breadth.

Therefore perimeter = 4.1 + 4.1 + 2.5 + 2.5

= 8.1 + 5

=13.1 mi

I hope this was helpful, Please mark as brainliest

Anna71 [15]2 years ago
8 0

Answer:

13.2 mi

Step-by-step explanation:

Perimeter of a rectangle

= 2 (L + W)

From the question

L = 4.1

W = 2.5

Using the above formula , we have P = 2 (4.1 + 2.5)

Using the distributive property

2x4.1 + 2x2.5

8.2 + 5

13.2mi

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Square $ABCD$ has area $200$. Point $E$ lies on side $\overline{BC}$. Points $F$ and $G$ are the midpoints of $\overline{AE}$ an
Charra [1.4K]

1. Consider square ABCD. You know that  

A_{ABCD}=AD^2=200,

then

AB=BC=CD=AD=10\sqrt{2}.

2. Consider traiangle AED. F is mipoint of AE and G is midpoint of DE, then FG is midline of triangle AED. This means that

FG=\dfrac{AD}{2}=\dfrac{10\sqrt{2} }{2}=5\sqrt{2}.

3. Consider trapezoid BFGC. Its area is

A_{BFGC}=\dfrac{FG+BC}{2}\cdot h, where h is the height of trapezoid and is equal to half of AB. Thus,

A_{BFGC}=\dfrac{FG+BC}{2}\cdot \dfrac{AB}{2}=\dfrac{5\sqrt{2}+10\sqrt{2}}{2}\cdot \dfrac{10\sqrt{2}}{2}=75.

4.

A_{BFGC}=A_{BFGE}+A_{EGC},\\A_{EGC}=A_{BFGC}-A_{BFGE}=75-34=41.

5. Note that angles EGC and CGD are supplementary and

\sin \angle CGD=\sin \angle EGC.

Then

A_{CGD}=\dfrac{1}{2}CG\cdot CD\cdot \sin \angle CGD=\dfrac{1}{2}CG\cdot EG\cdot \sin \angle CGE=A_{ACG}=41.

Answer: A_{CGD}=41.

8 0
2 years ago
If Machine A makes a yo-yo every five minutes and Machine B takes ten minutes. How many hours would it take them to make 20yo−yo
olga nikolaevna [1]

Answer:

Time in minutes = 66 2/3

Time in hours = 1.11

Step-by-step explanation:

Problem:

Time taken by both machine to make 20  yo-yo

let the time taken be x minutes

Given

Time taken by machine A  to make 1 yo-yo = 5 mins

No. of yo-yo made by machine A in x minutes = x/5

Time taken by machine B  to make 1 yo-yo = 10 mins

No. of yo-yo made by machine B in x minutes = x/10

Total no. of yo-yo made by both the machine = x/5 + x/10 = (2*x+x)/10

Total no. of yo-yo made by both the machine = 3x/10

But given that together they made 20 yo -yo

Thus,

3x/10 = 20

=> x = 20*10/3 = 200/3

Thus, it took 66 2/3 minutes to make 20 yo-yo by both of them

In one hour there is 60 minutes

Time taken in Hours will be = 200/3*60 = 200/180 = 10/9 = 1 1/9= 1.11 hours

4 0
2 years ago
Two candies are chosen randomly from a bag of Valentine’s Day candy containing 8 Snickers (S), 4 Peanut Butter Cups (P), and 2 B
Alexxandr [17]

Answer:

s

Step-by-step explanation:

5 0
2 years ago
A computer virus is trying to corrupt two files. The first file will be corrupted with probability 0.4. Independently of it, the
Ksivusya [100]

Answer:

P(X = 0) = 0.42

P(X = 1) = 0.46

P(X = 2) = 0.12

Step-by-step explanation:

We have these following probabilities:

40% probability that the first file is corrupted. So 60% probability that the first file is not corrupted.

30% probability that the second file is corrupted. So 70% probability that the second file is not corrupted.

Probability mass function

Probability of each outcome(0, 1 and 2 files corrupted).

No files corrupted:

60% probability that the first file is not corrupted.

70% probability that the second file is not corrupted.

So

P(X = 0) = 0.6*0.7 = 0.42

One file corrupted:

First one corrupted, second no.

40% probability that the first file is corrupted.

70% probability that the second file is not corrupted.

First one ok, second one corrupted.

60% probability that the first file is not corrupted.

30% probability that the second file is corrupted.

P(X = 1) = 0.4*0.7 + 0.6*0.3 = 0.46

Two files corrupted:

40% probability that the first file is corrupted.

30% probability that the second file is corrupted.

P(X = 2) = 0.4*0.3 = 0.12

8 0
2 years ago
A commercial laundry charges $5.25 per load. You have $31.50. Write and solve an inequality to find the greatest number of loads
4vir4ik [10]

Charges per load = $5.25

Total money = $31.50

As the situation says that charges are 5.25 and one has a total money of 31.50 so lets suppose the total load one has be 'w'

so equation becomes:

5.25w\leq31.50

solving it we get, w\leq6

So, option C is the correct answer.


5 0
2 years ago
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