Express the ratio 16:9 as a ratio to 1

Your utility company charges 13 cents per kilowatt-hour of electricity. What is the daily cost of keeping lit a 75 watt light bu

Tresset [83]

we know that

$1 Kw=1000 w$

The company charges $13$ cents per kilowatt-hour of electricity

$13 cents=0.13 dollars\\\\ 75w=\frac{75}{1000} kw\\\\ 15w=\frac{15}{1000} kw$

Step $1$

Find the cost for the light bulb

a) in one day

$\frac{75}{1000} *12=0.9\ kw\ hour$

$Cost=0.13*0.9$

Cost=$ $0.117$

b) In a year

$\frac{75}{1000} *12=0.9\ kw\ hour$

$0.9*365=328.5\ kw\ hour$

$Cost=0.13*328.5$

Cost=$ $42.71$

Step $2$

Find the cost for the led bulb

a) in one day

$\frac{15}{1000} *12=0.18\ kw\ hour$

$Cost=0.13*0.18$

Cost=$ $0.0234$

b) In a year

$\frac{15}{1000} *12=0.18\ kw\ hour$

$0.18*365=65.7\ kw\ hour$

$Cost=0.13*65.7$

Cost=$ $8.54$

Step $3$

Find the difference in cost

$Save=42.71-8.54\\ Save=34.17 dollars$

therefore

the answer is

$34.17 dollars$

3 0

2 years ago

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A scientist who studies teenage behavior was interested in determining if teenagers spend more time playing computer games then

Marina86 [1]

Answer:

- The amount of time greater than 10.2 hours for this year.

- The $P_{value}$ is 0.01358.

Step-by-step explanation:

Given information:

mean, X = 10.2 hours

sample, n = 15

using t distribution

test statistics = 2.822

$P_{value}$ = 2 x P( $t_{n-1}$ > test statistics)

= 2 x P( $t_{15-1}$ > 2.822)

= 2 x 0.00679

= 0.01358

$P_{value}$ is less than 0.10 which indicates that the amount of time greater than 10.2 hours for this year.

5 0

2 years ago

Two standard dice are rolled and their face values multiplied. What is the probability that the product is prime or ends in 0?

Trava [24]

The answer is 10/36 or 27.77%
here’s the working out

8 0

1 year ago

In a poker hand, John has a very strong hand and bets 5 dollars. The probability that Mary has a better hand is .04. If Mary had

mr_godi [17]

Answer:

When Mary raises the probability that she has a better hand is 0.273

Step-by-step explanation:

In the poker game it is given that the probability that Mary has a better hand than John is 0.04.

Let the event that Mary has a better hand than John be A.

Let the event that that Mary raises the stakes be B.

It is also given that if Mary has a better hand than John then she would raise with a probability of 0.9

Therefore p(B | A) = 0.9

If Mary has a poorer hand she will raise with a probability of 0.1

Therefore p(B | A') = 0.1

Given that Mary raises the probability that she has a better hand is given by

p(A | B)

$= \frac{p(A\cap B)}{p(B)}$ = $\frac{p(A)p(B | A)}{p(A)p(B | A) + p(A')p(B | A')} = \frac{(0.04 \times 0.9) }{(0.04 \times 0.9) + (0.96 \times 0.1)} = \frac{36}{36 + 96} = \frac{36}{132} = \frac{3}{11}$

= 0.273

So when Mary raises the probability that she has a better hand is 0.273

3 0

2 years ago

A 120 watt light bulb uses about 0.1 kilowatt of electricity per hour.if electricity costs $0.20 per kilowatt hour how much does

Ksivusya [100]

A 120 watt light bulb uses about 0.1 kilowatt of electricity per hour.if electricity costs $0.20 per kilowatt hour. Let's solve how much does it cost to have a bulb on for an hour. => 120 watt = 0.1 kilowatt per hour which costs 0.20 per kilowatt per => 0.1 kilowatt per hour * 0.20 = 0.02 dollars in an hour.

8 0

1 year ago

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