Cost of chicken wings at Buffalo Bills = 8 wings for $7
Cost of 1 wing at Buffalo Bills = 
Cost of chicken wings at Buffalo Mild Wings = 12 wings for $10
Cost of 1 wing at Buffalo Mild Wings = 
Cost of chicken wings at Wingers = 20 wings at $17
Cost of 1 wing at Wingers = 
Hence, comparing all the three costs per wing, we can see that Buffalo Mild Wings is serving chicken wings at lowest price of $0.833 per wing.
Answer:
The points (x,y,z) that respond to Ir-r0I =1, are all that describes the form
with:
-1+x₀<x<1+x₀
-1+y₀<y<1+y₀
-1+z₀<z<1+z₀
Step-by-step explanation:
All points required in this problem came from applying the definition of modulus of a vector:
Ir-r0I =1.

Answer:
3/5
Step-by-step explanation:
What divisor is represented by the synthetic division below? x + 5. One factor of x^3+x^2+x+1. If f(-5) = 0, what are all the factors of the function mc022-... -4 and 3. The polynomial function f(x) = 5x5 + 3x - 3 is graphed below. The root at point P maybe 3/5 3.
Answer:
g = 15 - m/28
Step-by-step explanation:
let g = gasoline
let m = miles
since you can drive 420 miles with 15 gallons of gas, you can drive 28 miles with one gallon (= 420/15 = 28)
e.g.
you drive 100 miles, then you will have:
g = 15 - 100/28 = 15 - 3.57 = 11.43 gallons of gas left
you drive 240 miles:
g = 15 - 240/28 = 6.43 gallons
9514 1404 393
Answer:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
142 fish
Step-by-step explanation:
A) The differential equation is modified by adding a -50 fish per year constant term:
(dN)/(dt) = (0.4)/(1200)N(1200-N) -50
__
B) The steady-state value of the fish population will be when N reaches the value that makes dN/dt = 0.
(0.4/1200)(N)(1200-N) -50 = 0
N(N-1200) = -(50)(1200)/0.4) . . . . rewrite so N^2 has a positive coefficient
N^2 -1200N + 600^2 = -150,000 +600^2 . . . . complete the square
(N -600)^2 = 210,000 . . . . . simplify
N = 600 + √210,000 ≈ 1058
This steady-state number of fish is ...
1200 - 1058 = 142 . . . . below the original carrying capacity