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1 year ago

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in a basketball game tatiana made 23 baskets . each of the baskets was worth either 2 or 3 points and Tatiana scored a total of

53 points . let x represent the number of two point baskets she made and y represent the number of 3 point baskets she made

2 answers:

natima [27]1 year ago

8 0

Here is the answer to you question!

Volgvan1 year ago

5 0

Answer:

<h2>n a basketball game tatiana made 23 baskets . each of the baskets was worth either 2 or 3 points and Tatiana scored a total of 53 points . let x represent the number of two point baskets she made and y represent the number of 3 point baskets she made</h2>

Step-by-step explanation:

We know that Tatiana made 23 baskets in a game.

$x$ represents two-points baskets, and $y$ represents three-points baskets.

If she scored 53 points, we would have the following relations

$x+y=23$ , which represents the total number of baskets.

$2x+3y=53$ , which represents the total number of points.

To solve this system, we multiply the first equation by -2, then sum and solve for $y$

$\left \{ {{-2x-2y=-46} \atop {2x+3y=53}} \right.\\ y=7$

Then, we replace this value to find the other one

$x+y=23\\x+7=23\\x=23-7\\x=16$

Therefore, Tatiana made 7 baskets of two points and 16 baskets of three points.

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1 year ago

TiliK225 [7]

Answer:

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2 years ago

Jane wishes to bake an apple pie for dessert. The baking instructions say that she should bake the pie in an oven at a constant

pychu [463]

Answer:

A=152

K= -Ln(0.5)/14

Step-by-step explanation:

You can obtain two equations with the given information:

T(14 minutes) = 114◦C

T(28 minutes)=152◦C

Therefore, you have to replace t=14, T=114 and t=28, T=152 in the given equation:

$114=190-Ae^{-14k} (I) \\152=190-Ae^{-28k}(II)$

Applying the following property of exponentials numbers in (II):

$e^{a}.e^{b}=e^{a+b}$

Therefore $e^{-28k}$ can be written as $e^{-14k}.e^{-14k}$

$152=190-Ae^{-14k}.e^{14k}$

Replacing (I) in the previous equation:

$152=190-76e^{-14k}$

Solving for k:

Subtracting 190 both sides, dividing by -76:

$0.5=e^{-14k}$

Applying the base e logarithm both sides:

Ln(0.5)= -14k

Dividing by -14:

k= -Ln(0.5)/14

Replacing k in (I) and solving for A:

$Ae^{-14(-Ln(0.5)/14)}=76\\Ae^{Ln(0.5)} =76\\A(0.5)=76$

Dividing by 0.5

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2 years ago

A person is standing 50 ft from a statue. The person looks up at an angle of elevation of 16o when staring at the top of the sta

NemiM [27]

Answer:

The height of the statue is 21.4 feet

Step-by-step explanation:

We are given

A person is standing 50 ft from a statue

The person looks up at an angle of elevation of 16 degree when staring at the top of the statue

hen the person looks down at an angle of depression of 8 degree when staring at the base of the statue

Firstly, we will draw diagram

In triangle ABF:

FC=50

we can use trig formula

$tan(16)=\frac{y}{50}$

$y=50tan(16)$

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now, we can find x

In triangle DEF:

we can use trig formula

$tan(8)=\frac{x}{50}$

$x=50tan(8)$

$x=7.0270ft$

we can see that

height of statue =x+y

so, the height of statue is

$=14.33727+7.0270$

$=21.4ft$

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2 years ago