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qwelly [4]
1 year ago
9

The gross income of Maurice Vaughn is $785 per week.His deductions are $42.25,FICA tax,$90.33,income tax,2% state tax,1% city ta

x and 3% retirement fund.what is his net income for one week
Mathematics
2 answers:
mixas84 [53]1 year ago
8 0

Gross income_____ $785.00

Less FICA__________-42.25

Less income tax_____-90.33

Less state taxª ______-15.70

Less city tax ² _______-7.85

Less retirement fund³_-23.55

---------------------------------------

David's net income__$605.32

=======================



ª$785 * .02 = $15.70

²$785 * .01 = _$7.85

³$785 * .03 = $23.55

boyakko [2]1 year ago
7 0
Gross income : 785 per week

deductions are :
FICA : 42.25
income tax : 90.33
2% state tax : 0.02(785) = 15.70
1% city tax : 0.01(785) = 7.85
3% retirement : 0.03(785) = 23.55
total deductions are : 42.25+90.33+15.70+7.85+23.55 = 179.68

gross pay - deductions = net pay
785 - 179.68 = net pay
605.32 = net pay <====

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1. Draw an accurate picture of the triangle in the coordinate axes, as shown in the attached picture.<span>

<span>2. Circumscribe a rectangle about the triangle, as shown in the picture. The coordinates of the points M, N, T are easily identifiable as shown in the picture.</span>

<span>3. The area of the triangle ABC is  The area of the rectangle - Area 1- Area 2- Area 3.</span>

Area 1 = 1/2(3*7)=21/2
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1 year ago
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JulijaS [17]

Answer:

Step-by-step explanation:

Hello!

To test if boys are better in math classes than girls two random samples were taken:

Sample 1

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n₁= 15

X[bar]₁= 82.3%

S₁= 5.6%

Sample 2

X₂: Score in the calculus of a girl

n₂= 12

X[bar]₂= 81.2%

S₂= 6.7%

To estimate per CI the difference between the mean percentage that boys obtained in calculus and the mean percentage that girls obtained in calculus, you need that both variables of interest come from normal populations.

To be able to use a pooled variance t-test you have to also assume that the population variances, although unknown, are equal.

Then you can calculate the interval as:

[(X[bar]_1-X[bar_2) ± t_{n_1+n_2-2;1-\alpha /2} * Sa*\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }]

Sa= \sqrt{\frac{(n_1-1)S^2_1+(n_2-1)S^2_2}{n_1+n_2-2} } = \sqrt{\frac{14*(5.6^2)+11*(6.7^2)}{15+12-2} }= 6.108= 6.11

t_{n_1+n_2-2;1-\alpha /2}= t_{15+12-2;1-0.05}= t_{25;0.95}= 1.708

[(82.3-81.2) ± 1.708* (6.11*\sqrt{\frac{1}{15}+\frac{1}{12}  }]

[-2.94; 5.14]

Using a 90% confidence level you'd expect the interval [-2.94; 5.14] to contain the true value of the difference between the average percentage obtained in calculus by boys and the average percentage obtained in calculus by girls.

I hope this helps!

3 0
1 year ago
Rate at which risk of down syndrome is changing is approximated by function r(x) = 0.004641x2 − 0.3012x + 4.9 (20 ≤ x ≤ 45) wher
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The rate of change of the risk of down syndrome (in percentage of births per year) is
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The function giving risk as a percentage of births when maternal age is x is the integral of r(x). That is,
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each can costs 19.75, which means that the total cost is:

19.75 * 3 = 59.25 euros

6 0
2 years ago
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