There are many expressions that have solution 4. some are:
3+1 = 4
2+2 = 4
5-1 = 4
7-3 =4
8-4 = 4
...........
Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Answer: I think its D. 1:5
Step-by-step explanation:
but im not surr
43.66 minutes
4^2*5+20*x-x^2/2=0
Or
Initial volume of water plus rate of water in minus rate of water out
Answer:
D. on Edg 2020
Step-by-step explanation:
You are welcome, I helped better than that other guy!!!
