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solniwko [45]
2 years ago
13

Dmitri wants to cover the top and sides of this box with glass tiles that are 1 cm square.How many tiles will be need?

Mathematics
2 answers:
tatiyna2 years ago
7 0

Answer:

854 glass tiles

Step-by-step explanation:

first you have to find the area of each side so that you can add them up together.

(20*9)+(20*9)+(13*9)+(13*9)+(20*13)

Simplify

[(20*9)2] +[(13*9)2]+(20*13)

360+234+260

854

KengaRu [80]2 years ago
6 0

Answer:

372

Step-by-step explanation:

We are given that the dimensions of the box are,

Length = 15 cm, Width = 20 cm and Height = 9 cm.

We know that the box represents a cuboid.

Since, surface area of a cuboid = L×W + 2×L×H + 2×W×H

Thus, the surface area of the box = 15×20 + 2×15×9 + 2×20×9

i.e. Surface area = 300 + 270 + 360

i.e. Surface area = 930.

Thus, the surface area of the box is 930 cm² i.e. 9300 mm².

Further, the sides of the tiles are 5 mm and the tile represents a square.

So, the surface area of the tile = 5 × 5 = 25 mm².

This gives us that,

Number of tiles required to cover the box=  372.

Hence, Dmitri requires 372 tiles to cover the box

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Ivenika [448]

Answer:

Total number of trials is 35.

Step-by-step explanation:

Given : Me and my friend have a hula hoop competition. I win 3 out of every 7 trials. My friend wins 5 more trials than me.  

To find : How many trials are in the competition?

Solution :

Probability of my winning is 3 out of 7 trials =\frac{3}{7}

and probability of my friend's winning is  =1-\frac{3}{7}=\frac{4}{7}  

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and my friend's score after n trials   =\frac{4n}{7}

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\frac{n}{7}=5\\n=7\times5=35

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We can also verify our answer by placing value of n,

After 35 trials I will win \frac{3\times 35}{7}=15 trials

and my friend will win \frac{4\times 35}{7}=20  trials.

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3 0
2 years ago
6 use fermat’s theorem to find a number x between 0 and 28 with x85 congruent to 6 modulo 29. (
Ulleksa [173]
If

x^{85}\equiv6\mod29

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\dfrac{x^{85}}6\equiv1\mod29

By Fermat's little theorem, if a is not divisible by a prime p, then

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This works for x=6; in this case, we would have

\dfrac{6^{85}}6=6^{84}=\left(6^3\right)^{28}=\left(6^3\right)^{29-1}\equiv1\mod29
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Answer:

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Step-by-step explanation:

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