Question

A division of a company has over 200 employees, 40% of which are male. Each month, the company randomly

Answer 1

Answer:

$\mu_p=3.2\\\\\sigma_p=0.2$

Step-by-step explanation:

-The number of males in the company is:

$Males, n=\%\ Males\times Total\\\\=0.4\times 200\\\\=80$

#Given the proportion of males in the population is 40%(p=0.4) and the sample size, n=8

-The mean and standard deviation of a sample proportion is calculated as follows:

$\mu=np\\\\=0.4\times 8\\\\\\\\=3.2\\\\\sigma_p=\sqrt{\frac{p(1-p)}{n}}\\\\\\=\sqrt{\frac{0.4(1-0.4)}{8}}\\\\\\\\=0.1732\approx0.2$

Hence, the mean of males is 3.2 and the standard deviation is 0.2

Answer 2

Answer:

mean: 3.2 standard deviation: 1.4

Step-by-step explanation:

its correct