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Burka [1]
2 years ago
9

Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step

s below. What was Jada’s error?
Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction
Negative StartFraction 4 over 9 EndFraction (Negative StartFraction 9 over 4 EndFraction) = StartFraction x over 108 EndFraction (Negative StartFraction 9 over 4 EndFraction)
x = negative StartFraction 1 over 48 EndFraction

Jada should have multiplied both sides of the equation by 108.
Jada should have multiplied both sides of the equation by Negative StartFraction 4 over 9 EndFraction.
The product of Negative StartFraction 9 over 4 EndFraction and StartFraction 1 over 108 EndFraction is not equal to Negative StartFraction 1 over 48 EndFraction.
The product of Negative StartFraction 9 over 4 EndFraction and 108 should have been the value of x.
Mark this and return

Mathematics
2 answers:
zavuch27 [327]2 years ago
6 0

Answer:first option

Step-by-step explanation:

I taked test

Lilit [14]2 years ago
3 0

Answer: First option.

Step-by-step explanation:

The complete exercise is attached.

In order to solve this exercise, it is necessary to remember the following property:

The Multiplication property of Equality states that:

If\ a=b\ then\ a*c=b*c

In this case, the equation that Jada had is the folllowing:

-\frac{4}{9}=\frac{x}{108}

Jada needed to solve for the variable "x" in order to find its value.

The correct procedure to solve for for "x" is to multiply both sides of the equation by 108. Then, you get:

(108)(-\frac{4}{9})=(\frac{x}{108})(108)\\\\-48=x

As you can notice in the picture, Jada did not multiply both sides of the equation by 108, but multiplied the left side by -\frac{4}{9}<em>  </em>and the right side by -\frac{9}{4}.

Therefore,you can conclude that Jada should have multiplied both sides of the equation by 108.

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Consider 8x2 - 48x = -104. Write the equation so that x2 – 6x + (blank) = –13 + (blank)
Monica [59]

Answer:

That (blank) is 9.

Step-by-step explanation:

Please write 8x^2 - 48x = -104, with " ^ " indicating exponentiation.  Thanks.

This sounds like a perfect example of "completing the square."

First, factor 8x^2 - 48x = -104:  8(x^2 - 6x = -13).

If we focus SOLELY on x^2 - 6x = -13, it's just a little easier to "complete the square."  Take half of the coefficient of x (which here is -6), and square that result (which here is (-3)^2, or 9.  Now add 9 both sides of x^2 - 6x = -13:

x^2 - 6x + 9 = -13 + 9.  Note:  The "blank" in the problem statement is 9.  

We could go ahead and solve this, tho' we weren't asked to do so.  Rewrite x^2 - 6x + 9 as (x - 3)^2:

x^2 - 6x = -13 then becomes (x - 3)^2 = 4.  To solve for x, take the sqrt of both sides of this latest result, obtaining x - 3 = plus or minus 2.  Add 3 to both sides to isolate x:  x = 3 plus or minus 2.

Thus, x = 5 or x = 1.  

5 0
2 years ago
Read 2 more answers
باستعمال log4 2=0.5 فإن قيمة log4 32 هي
11Alexandr11 [23.1K]

Answer:

\mathbf{\log_432}=2.5

Step-by-step explanation:

\log_42=0.5

حن بحاجة إلى إيجاد\log_432

دع\log_432=x

\log_42\times 2\times 2\times 2\times 2=x

\Rightarrow x=\log_42^5

\Rightarrow x=5\log_42   [\because \log_ab^x=x\log_ab]

\Rightarrow x=5\times0.5

\Rightarrow x=2.5

\mathbf{\therefore\log_432=2.5}

7 0
2 years ago
In Quebec, 90 percent of the population subscribes to the Roman Catholic religion. In a random sample of eight Quebecois, find t
AysviL [449]

Answer:

Probability that the sample contains at least five Roman Catholics = 0.995 .

Step-by-step explanation:

We are given that In Quebec, 90 percent of the population subscribes to the Roman Catholic religion.

The Binomial distribution probability is given by;

 P(X = r) = \binom{n}{r}p^{r}(1-p)^{n-r} for x = 0,1,2,3,.......

Here, n = number of trials which is 8 in our case

         r = no. of success which is at least 5 in our case

         p = probability of success which is probability of Roman Catholic of

                 0.90 in our case

So, P(X >= 5) = P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8)

= \binom{8}{5}0.9^{5}(1-0.9)^{8-5} + \binom{8}{6}0.9^{6}(1-0.9)^{8-6} + \binom{8}{7}0.9^{7}(1-0.9)^{8-7} + \binom{8}{8}0.9^{8}(1-0.9)^{8-8}

= 56 * 0.9^{5} * (0.1)^{3} + 28 * 0.9^{6} * (0.1)^{2} + 8 * 0.9^{7} * (0.1)^{1} + 1 * 0.9^{8}

= 0.995

Therefore, probability that the sample contains at least five Roman Catholics is 0.995.

3 0
2 years ago
Seth’s father is thinking of buying his son a six-month movie pass for $40. With the pass, matinees cost $1.00. If matinees are
Ymorist [56]

Answer:

In order for it to benefit his father to buy the pass Seth have to attend the movies for 11 times.

Step-by-step explanation:

Given:

Cost of movie pass = $40

Cost per matinees with pass = $1.00

Cost per matinees without pass = $3.50

To Find:

Number of times must Seth attend in order for it to benefit his father to buy the pass = ?

Solution:

Let x be the number of times he wants to visit

To profit his father

The number of visits without pass =  the number of visits with passin the cost  of $3.50

Then, without pass if he visits for x times then the cost will be  = 3.50x

Also with pass, the number of times he can visit the pass  =  \frac{40}{3.50}

then

\frac{350 x}{3.50} = \frac{40}{3.50}

3.50x = 40

x = \frac{40}{3.50}

x =  11.42

x = 11 (approx)

3 0
2 years ago
If Johnny had 20 complete living room outfits, disregard color scheme, how many different sets of five complete outfits could be
S_A_V [24]
The answer to this question is 5
3 0
2 years ago
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