Answer:
<h2>Second choice.</h2>
Step-by-step explanation:
The given inequality is

Let's solve for 

Basically, the solution of the given inquality is set with all real numbers which are equal or less than -8. So, the solution must indicate a blue line starting at -8 pointing to its left.
Therefore, the second choice represents the solution to the given inequality.
1) The outcomes for rolling two dice, the sample space, is as follows:
(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)
(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)
(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)
(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)
(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)
(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)
There are 36 outcomes in the sample space.
2) The ways to roll an odd sum when rolling two dice are:
(1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (3, 6), (4, 1), (4, 3), (4, 5), (5, 2), (5, 4), (5, 6), (6, 1), (6, 3), (6, 5). There are 18 outcomes in this event.
3) The probability of rolling an odd sum is 18/36 = 1/2 = 0.5
Answer:
True, True, False, True, False, True
Step-by-step explanation:
<u>CDs have a higher mean than digital</u>
<u />
Let's check. CD mean is (1000 + 800 + 800 + 600 + 400 + 200)/6 = 633.33
Digital mean: (100 + 300 + 300 + 500 + 700 + 900)/6 = 466.67
CD's mean is higher. Since you are dividing byt he same number you also could have just added the amount and found which was a larger number. But yes, this is true.
<u>The range of digital is 800</u>
<u />
The range is the highest number inus the lowest number. For digital the highest is 900 and lowest is 100 so the ange is 900-100 = 800. So this is true.
<u>The median of CDs is 400.
</u>
<u />
The median is the middle value for odd numbers of values, or the average of the two middle values. 6 total values means you have to take the third and fourth and average them. in CDs the middle values are 800 and 600, the average is 700, so that is what the median is. this is false.
<u>Both have the same interquartile range.
</u>
<u />
Interquartile range is to find the middle number or numbers like in median, then take the two parts it is split into and find the "median" of those. Then subtract the larger one fromt he smaller one.
IQR of CD the first half is 200, 400, 600 so the middle here is 400, second half has a middle number of 800 so IQR here is 800-400=400
IQR of digital is 700-300 = 400 so yes both are the same.
<u>Both have the same median</u>
<u />
We know the medan of CDs is 700 then findign the median of digital is (300+500)/2 = 400. So no, the medians are not the same.
<u>Digital’s mean is around 467.
</u>
<u />
We founf the mean for digital to be 466.67 which rounds up to 467, So I would say it is true.
The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
Every day, Jorge buys a lottery ticket. Each ticket has a 0.16 probability of winning a prize. After six days, what is the probability that Jorge has won at least one prize? Round your answer to four decimal places.
Answer:
The probability that Jorge has won at least one prize after six days is
P(at least 1 win) = 0.6487
Step-by-step explanation:
Every day, Jorge buys a lottery ticket which has a 0.16 chance of winning a prize.
We want to find out the probability that Jorge has won at least one prize after six days.
P(at least 1 win) = 1 - P(not winning for 6 days)
We know that the probability of winning is 0.16 then the probability of not winning is
P(not winning) = 1 - 0.16 = 0.84
For 6 days,
P(not winning for 6 days) = 0.84×0.84×0.84×0.84×0.84×0.84
P(not winning for 6 days) = 0.84⁶
P(not winning for 6 days) = 0.3513
Finally,
P(at least 1 win) = 1 - P(not winning for 6 days)
P(at least 1 win) = 1 - 0.3513
P(at least 1 win) = 0.6487