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Valentin [98]
1 year ago
10

Write the equation of the line that passes through the points (7, —4) and (—1 , 3) , first in point -slope form , and then slope

- intercept form
Mathematics
1 answer:
ipn [44]1 year ago
5 0

Answer:

The slope of the line is -7/8

The point slope-form is y+4=(-7/8)(x-7)

The slope-intercept form is y=(-7/8)x+(17/8)

Step-by-step explanation:

You have to find the slope first using m=y2-y1 divided by x2-x1. After you found the slope of the line, you use one of the points to plug it into the point-slope form which is y-y1=m(x-x1). After you have done that, you would have convert this equation into slope-intercept form which is y=mx + b. In order to convert it, you have to multiply m with x and x1. Then you would have to get rid of y1 by doing the opposite of what y1 is. Finally, you would take the opposite of y1 and add it to the other side of the equation.

Really hope this helps! :)

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Hello, I was wondering if someone would be able to help me with this problem I'm on. Thanks :)
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2/10 EOM price = $8,400 - (2% discount)

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Stefanie is planning a 610-mile trip. Her car’s EPA rating is 34 mpg on the highway. How many gallons of gas will she require fo
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The cafe where you work just ran out of coffee, and you are at the store to buy 112 pounds of coffee. You have put a can with 34
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Answer:

78

Step-by-step explanation:

The total you are buying is 112 pounds.  The can you have picked up is 34 pounds; this leaves

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7 0
1 year ago
Read 2 more answers
A member of a student team playing an interactive marketing game received the fol- lowing computer output when studying the rela
nirvana33 [79]

Answer:

p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91

So on this case for the significance level assumed \alpha=0.05 we see that p_v >\alpha so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

Step-by-step explanation:

Let's suppose that we have the following linear model:

y= \beta_o +\beta_1 X

Where Y is the dependent variable and X the independent variable. \beta_0 represent the intercept and \beta_1 the slope.  

In order to estimate the coefficients \beta_0 ,\beta_1 we can use least squares procedure.  

If we are interested in analyze if we have a significant relationship between the dependent and the independent variable we can use the following system of hypothesis:

Null Hypothesis: \beta_1 = 0

Alternative hypothesis: \beta_1 \neq 0

Or in other words we want to check is our slope is significant (X have an effect in the Y variable )

In order to conduct this test we are assuming the following conditions:

a) We have linear relationship between Y and X

b) We have the same probability distribution for the variable Y with the same deviation for each value of the independent variable

c) We assume that the Y values are independent and the distribution of Y is normal  

The significance level assumed on this case is \alpha=0.05

The standard error for the slope is given by this formula:

SE_{\beta_1}=\frac{\sqrt{\frac{\sum (y_i -\hat y_i)^2}{n-2}}}{\sqrt{\sum (X_i -\bar X)^2}}

Th degrees of freedom for a linear regression is given by df=n-2 since we need to estimate the value for the slope and the intercept.  

In order to test the hypothesis the statistic is given by:

t=\frac{\hat \beta_1}{SE_{\beta_1}}

The p value on this case would be given by:

p_v = 2*P(t_{n-2} > |t_{calc}|)= 0.91

So on this case for the significance level assumed \alpha=0.05 we see that p_v >\alpha so then we can conclude that the result is NOT significant. And we don't have enough evidence to reject the null hypothesis.

So on this case is not appropiate say that :"the more we spend on advertising this product, the fewer units we sell" since the slope for this case is not significant.

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1 1/5 is the answer
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