Question

Which are the solutions of x2 = –13x – 4? 0, 13 0, –13

Answer 1

Answer:

Option 3 and 4 - 0,-13

Step-by-step explanation:

Given : Expression $x^2=-13x-4$

To find : What are the solutions?

Solution :

The quadratic formula of the quadratic equation $ax^2+bx+c=0$ is

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Comparing with general equation, $x^2+13x+4=0$

where, a=1 ,b=13, c=4

Substitute in the formula,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\frac{-13\pm\sqrt{13^2-4(1)(4)}}{2(1)}$

$x=\frac{-13\pm\sqrt{169-16}}{2}$

$x=\frac{-13\pm\sqrt{153}}{2}$

$x=\frac{-13+\sqrt{153}}{2},\frac{-13-\sqrt{153}}{2}$

The value of x is $x=-0.315,-12.68$

Approximately the solution of the expression is x=0,-13.

Answer 2

It's defiantly not C. I made a 90%  but missed this question. I hope this helps you cross it down.  My next guess would be D.