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iVinArrow [24]
2 years ago
8

The volume of a rectangular prism is (x3 – 3x2 + 5x – 3), and the area of its base is (x2 – 2). If the volume of a rectangular p

rism is the product of its base area and height, what is the height of the prism?
x minus 3 + StartFraction 7 x minus 9 Over x squared minus 2 EndFraction
x minus 3 + StartFraction 7 x minus 9 Over x cubed minus 3 x squared + 5 x minus 3 EndFraction
x minus 3 + StartFraction 7 x + 3 Over x squared minus 2 EndFraction
x minus 3 + StartFraction 7 x + 3 Over x cubed minus 3 x squared + 5 x minus 3 EndFraction
Mathematics
2 answers:
IrinaK [193]2 years ago
8 0
The first one is the answer because
djverab [1.8K]2 years ago
5 0

Answer:

A. x - 3 + 7x - 9/x^2 - 2

did test on edge, got 100%

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Identify the variation as direct, inverse, joint or combined. A = r²
myrzilka [38]

Answer : Direct Variation

Question :

Identify the variation as direct, inverse, joint or combined. A = \pi r^2

We know direct variation is y = kx

Where k is the constant of proportionality

When value of x increases then y also increases. when x value decreases then y value decreases.

The value of y depends on value of x It means y is directly proportional to x.

Hence A = \pi r^2 is a direct variation.


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Devonte is not correct because the interquartile range is less for Spanish.

Step-by-step explanation:

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Joe wants to paint the outside of a wooden box. He needs to find the surface area of the box
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4*2=8

4*1.5=6

2*1.5=3

8*2=16

2*6=12

2*3=6

16+12+6=34 ft

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Round 3659 to the nearest thousand
Kryger [21]
It is 4,000. :P
The 6 in the hundreds tells you to round up. 4 and under, keep it. 5 and up, raise it by one. :)
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A random draw is being designed for 210 participants. A single winner is to be chosen, and all the participants must have an equ
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Answer: The correct number of balls is (b) 4.

Step-by-step explanation:  Given that a single winner is to be chosen in a random draw designed for 210 participants. Also, there is an equal probability of winning for each participant.

We are using 10 balls, numbered through 0 to 9. We are to find the number of balls which needs to be picked up, regardless of order, so that each of the 210 participants can be assigned a unique set of numbers.

Let 'r' represents the number of balls to be picked up.

Since we are choosing from 10 balls, so we must have

^{10}C_r=210.

The value of 'r' can be any one of 0, 1, 2, . . , 10.

Now,

if r = 1, then

^{10}C_1=\dfrac{10!}{1!(10-1)!}=\dfrac{10!}{1!9!}=\dfrac{10\times 9!}{1\times 9!}=10

If r = 2, then

^{10}C_2=\dfrac{10!}{2!(10-2)!}=\dfrac{10!}{2!8!}=\dfrac{10\times 9\times 8!}{2\times 1\times 8!}=45

If r = 3, then

^{10}C_3=\dfrac{10!}{3!(10-3)!}=\dfrac{10!}{3!7!}=\dfrac{10\times 9\times 8\times 7!}{3\times 2\times 1\times 7!}=120

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Therefore, we need to pick 4 balls so that each participant can be assigned a unique set of numbers.

Thus, (b) is the correct option.

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2 years ago
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