Answer:
The inverse is ±sqrt((x-1))/ 4
Step-by-step explanation:
y = 16x^2 + 1
To find the inverse, exchange x and y
x = 16 y^2 +1
Then solve for y
Subtract 1
x-1 = 16 y^2
Divide by 16
(x-1)/16 = y^2
Take the square root of each side
±sqrt((x-1)/16) = sqrt(y^2)
±sqrt((x-1))/ sqrt(16) = y
±sqrt((x-1))/ 4 = y
The inverse is ±sqrt((x-1))/ 4
Answer:
The amount of work required to remove all of the water by pumping it over the side = 3.12 × 10⁶ lbs.ft
Step-by-step explanation:
Work done in moving anything from point A to point B = Fx
For this setup,
If we take an elemental vertical height, dx, The volume would be A.dx
where A = Cross sectional Area = πr² = π(18)² = 1017.88 ft²
dV = 1017.88 dx
The elemental force on that part will be
dF = ρg dV
ρg = 63.8 lbs/ft³
dF = 63.8 × 1017.88 dx = 64940.5 dx
F = ∫dF = 64940.5 dx
W = Fx = (∫dF)x = ∫ 64940.5x dx = 64940.5 ∫ xdx
We'll be integrating from (11 - 6) ft to 11 ft because that's the total height it'll be pumped through
W = 64940.5 (x²/2)¹¹₅ = 64940.5((11² - 5²)/2) = 3.12 × 10⁶ lbs.ft
<h3>
Hey!</h3>
<em><u>To solve the missing number of the original amount of gallons that were in the tank is simply by adding the two numbers we have: </u></em>
<em><u></u></em>
9+3= 12 gallons
<u><em>To make sure 12 was the original number, subtract 12 from 9. </em></u>
<u><em /></u>
<u><em>12-9= 3 gallons </em></u>
So your answer to your question is 12 gallons!
Hope this helped! °ω°
⁻⁻Using Sine ratio: opposite / Hypotenuse
Opposite to angle A = 24, Hypotenuse = 25
Sin A = 24 / 25
Sin A = 0.96
A = Sin⁻¹(0.96) Use a calculator.
A ≈73.74°
A ≈ 73.7°
∠A + ∠B = 90° Since it is a right angled triangle.
∠B = 90° - ∠A
∠B = 90° - 73.7°
∠B = 16.3°
Answer:
(c.) m∠A ≈ 73.7°, m∠B ≈ 16.3°, m∠C = 90°
June :
900 + 0.02(48,500) + 0.018(48500 - 17500) =
900 + 970 + 558 = 2428 <==
July :
900 + .02(50,200) + 0.018(50200 - 17500) =
900 + 1004 + 588.60 = 2492.60 <===
