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soldier1979 [14.2K]
2 years ago
10

Marginal Revenue

Mathematics
1 answer:
kvv77 [185]2 years ago
6 0

Answer:

Step-by-step explanation:

a) Revenue function us derives by taking the product of the number of yachts and the demand function p given. Mathematically,

R(x) = xp(x)

Given p(x) = 700 − 0.01x ln(x)

R(x) = x{700 − 0.01x ln(x)}

R(x) = 700x - x(0.01x ln(x))

R(x) = 700x - 0.01x²lnx

Hence the revenue function R(x) is expressed as R(x) = 700x - 0.01x²lnx

Marginal revenue function is derived by finding the derivative of the revenue function R(x). On differentiating;

d{R(x)}/dx = 700 - 0.01{x²(1/x)+2xlnx} (note that product rule was used to differentiate the function in parenthesis).

d{R(x)}/dx = 700 - 0.01{x+2xlnx}

Open the parenthesis

d{R(x)}/dx = 700 - 0.01x-0.02xlnx

Hence the marginal revenue function R'(x) is expressed as 700 - 0.01x-0.02xlnx.

b) In order to estimate the revenue to be realized from the sale of the 375th 34 ft Sundancer yacht, we will simply substitute the variable x = 375 into the revenue function R(x)

Given R(x) = 700x - 0.01x²lnx

R(375) = 700(375) - 0.01(375)²ln(375)

R(375) = 262500-1406.25ln(375)

R(375) = 262500-8334.74

R(375) = 254,165.26

Hence the revenue realized from the sale is approximately $254,165

For the Marginal revenue Function,

R'(x) = 700−0.01x−0.02xln(x)

R'(375) = 700−0.01(375)−0.02(375)ln(375)

R'(375) = 700−3.75−0.02(375)ln(375)

R'(375) = 700-3.75-44.45

R'(375) = 651.8

The marginal revenue is approximately $652

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Answer:

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Step-by-step explanation:

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In this problem, the measures are the weight of the cheese and the price. As the weight increases, so does the price. It means that this is a direct rule of three.

Solution:

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