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frosja888 [35]
2 years ago
15

A lawyer owns 4 pairs of pants, 5 dress shirts and 6 ties. How many days can the lawyer go without wearing the same combination

of three items?
Mathematics
2 answers:
SIZIF [17.4K]2 years ago
4 0
4 ways to wear all pants
5 ways to wear shirts
6 ways to wear ties
4*5*6=120 different combos
think of it like this

eample
2 pairs of pants and 3 pairs of shirts
a,b are the pants, and c,d,e are the shirts
the ways are below
ac
ad
ae
bc
bd
be
2*3=6, 6 ways

answer is 120 days
stiv31 [10]2 years ago
3 0
I believe that to calculate this, you do 4x5x6 and then divide it by 3, to get 40
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