Answer:

So then P =11000 is the minimum that the least populated district could have.
Step-by-step explanation:
We have a big total of N = 132000 for the population.
And we know that we divide this population into 11 districts
And we have this info given "no district is to have a population that is more than 10 percent greater than the population of any other district"
Let's assume that P represent our minimum value for a district in the population. The range of possible values for the population of each district would be between P and 1.1 P
The interest on this case is find the minimum value for P and in order to do this we can assume that 1 district present the minimum and the other 10 the maximum value 1.1P in order to find which value of P satisfy this condition, and we have this:


So then P =11000 is the minimum that the least populated district could have.
Original Ratio of 1 in = 7 ft so 3 in = 21 ft
Now, New ratio 1 in = x ft so 3 in = 27ft
1/x = 3/27
cross multiply a/b = c/d ad = bc
1/x = 3/27
3x = 27
x = 9
1 in represents 9 ft
Answer:
47 pounds i think \/'_'\/
Step-by-step explanation: