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attashe74 [19]
2 years ago
8

The diameter of small Nerf balls manufactured overseas is expected to be approximately normally distributed with a mean of 5.2 i

nches and a standard deviation of .08 inches. Suppose a random sample of 20 balls is selected. Calculate the mean of the sampling distribution of the sample mean.
Mathematics
1 answer:
ioda2 years ago
7 0

Answer:

5.2 inches

Step-by-step explanation:

The diameter of small Nerf balls follows normally distribution with mean 5.2 inches and standard deviation 0.08 inches.

We have to calculate the mean of sampling distribution when 20 balls are selected randomly.

Here, μ=5.2 and σ=0.08.

We know that mean of sampling distribution for mean is equal to the population mean.

mean of sampling distribution for mean= μxbar=μ= 5.2

Thus, mean of the sampling distribution of the sample mean is 5.2 inches

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2 years ago
a rectangle rug has a perimeter of 146 ft the width of the rug is 5 feet more than three times the length find the length and th
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Answer:

The length = 56 feet and the width = 17 feet.

Step-by-step explanation:

We can set up 2 equations to solve this. Let the length of the rug be x, then

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The perimeter = 2x + 2w = 146 so we have the 2 equations:

x = 3w + 5

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Now we substitute for x in the second equation:

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Since, Here the vertices of the rhombus defg are d(1, 4), e(4, 0), f(1, –4), and g(–2, 0).

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