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alina1380 [7]
2 years ago
14

Crop yield is the ratio of the number of bushels harvested to the number of acres used for the harvest. this year, a large farm

harvested rice from 690 acres of farmland. the crop yield was 7,553 bushels per acre. approximately how many bushels of rice were harvested? 0.1 million bushels 5.2 million bushels 8.2 million bushels 10.9 million bushels
Mathematics
2 answers:
Fiesta28 [93]2 years ago
6 0
5.2 million bushels just multiply 7553x690=5211570 ans then round it up to 5.2million
Marizza181 [45]2 years ago
3 0

The answer is <em>B. 5.2 million bushels.</em>

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Emma was about to finish grocery shopping when she noticed that cans of soup were on sale. Her total bill for groceries would be
Alinara [238K]

Answer:

3rd option: B(C)= 1.79C +86.03

Step-by-step explanation:

Total bill

= cost of cans(number of cans) +cost of other groceries

Let the cost of other groceries be G, and the cost of cans be X.

Given that number of cans= C,

Total bill= XC +G

If 2 cans were purchased,

2X+G= 89.61 -----(1)

If 5 cans were purchased,

5X +G= 94.98 -----(2)

(2) -(1):

(5X +G) -(2X +G)= 94.98 -89.61

5X +G -2x -G= 5.37

3X= 5.37

X= 5.37 ÷3 <em>(</em><em>÷</em><em>3</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

X= 1.79

Subst. X= 1.79 into (1):

2(1.79) +G= 89.61

3.58 +G= 89.61

G= 89.61 -3.58 <em>(</em><em>-3.58</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

G= 86.03 <em>(</em><em>simplify</em><em>)</em>

Total bill

= XC +G

= 1.79C +86.03

Thus, the function is B(C)= 1.79C +86.03.

3 0
2 years ago
Which expression is equivalent to b^-2/ab^-3 assume a=0 b=0
andrey2020 [161]
B^-2/ab^-3 = b^-2/b^-3 x 1/a = b^[-2-(-3)] x 1/a = b x 1/a = b/a
3 0
2 years ago
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The traffic engineer for a large city is conducting a study on traffic flow at a certain intersection near the city administrati
barxatty [35]

Answer:

e) The number of minutes for a car to get from the intersection to the administration building

Step-by-step explanation:

Continuous Data:

Data that can take any value (an infinite number of values) within a certain range.

For example, the statistics of a group of people form continuous data, but the number of people in that group form discrete data.

Inglés

In this case, counting items such as cars, bicycles, people, are considered discrete data. They exclusively take integer values.

But time data can take continuous values.

8 0
2 years ago
An annexation suit against a county subdivision of 1200 residences is being considered by a neighboring city. If the occupants o
Sunny_sXe [5.5K]

Answer:

Probability that in a random sample of 10 at least 3 favor the annexation suit is 0.9453.

Step-by-step explanation:

We are given that an annexation suit against a county subdivision of 1200 residences is being considered by a neighboring city. The occupants of half the residences object to being annexed.

Also, a random sample of 10 residents is taken.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 10 residents

            r = number of success = at least 3

           p = probability of success which in our question is probability that

                 residents favor the annexation suit, which is calculated as below;

p = \frac{\text{Number of residents favoring the annexation suit }}{\text{Total number of residents considered } } = \frac{600}{1200} = 0.50

<em>LET X = Number of residents favoring the annexation suit</em>

So, it means X ~ Binom(n=10, p=0.50)

Now, Probability that in a random sample of 10 at least 3 favor the annexation suit is given by = P(X \geq 3)

 P(X \geq 3)  = 1 - P(X < 3) = 1 - P(X \leq 2)

               = 1 - [P(X = 0) + P(X = 1) + P(X = 2)]

= 1- [\binom{10}{0}\times 0.50^{0} \times (1-0.50)^{10-0} + \binom{10}{1}\times 0.50^{1} \times (1-0.50)^{10-1} +\binom{10}{2}\times 0.50^{2} \times (1-0.50)^{10-2}]

= 1-[ 1 \times 1  \times 0.50^{10}+10 \times 0.50^{1}  \times 0.50^{9}+45 \times 0.50^{2}  \times 0.50^{8}]

= 1-[ 0.50^{10}+10 \times 0.50^{10}+45 \times  0.50^{10}]

= 1-0.50^{10}[ 1+10 +45 ] = 1-0.50^{10} \times 56

                                      = 0.9453

Therefore, Probability that in a random sample of 10 at least 3 favor the annexation suit is 0.9453.

8 0
2 years ago
Simplify 2n+5.5-0.9n-8+4.5p
Anettt [7]
The answer is 
1.1n+4.5p-2.5

7 0
2 years ago
Read 2 more answers
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