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2 years ago

6

The growth in the mouse population at a certain county dump can be modeled by the exponential function A(t)= 906e0.012t, where t

is the number of months since the population was first recorded. Estimate the population after 36 months.

1 answer:

tatyana61 [14]2 years ago

5 0

Answer:

$A(t) = 906 e^{0.012t}$

Where t is the number of months since the population was first recorded. And we want to find the population after 36 months so we need to replace t=36 months into the function and we got:

$A(36) = 906 e^{0.012*36}= 1395.54$

So then we can conclude that after 36 months the population of mouse is between 1385 and 1396.

Step-by-step explanation:

We know that the population can be represented with this formula:

$A(t) = 906 e^{0.012t}$

Where t is the number of months since the population was first recorded. And we want to find the population after 36 months so we need to replace t=36 monthsinto the function and we got:

$A(36) = 906 e^{0.012*36}= 1395.54$

So then we can conclude that after 36 months the population of mouse is between 1385 and 1396.

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A salesman normally makes a sale (closes) on % of his presentations. Assuming the presentations are independent, find the pro

Tamiku [17]

Answer:

$(a)\ 0.0864$

$(b)\ 0.096$

$(c)\ 0.24$

$(d)\ 0.936$

Step-by-step explanation:

Given

$p \to$ close

$q \to$ fail to close

$p = 60\%$

$p = 0.60$

First, calculate the value of q

Using complement rule

$q = 1 - p$

$q = 1 - 0.60$

$q = 0.40$

So, we have:

$p = 0.60$ and $q = 0.40$

Solving (a): Fails to close on the 4th attempt

This means that he closes the first three attempts. The event is represented as: p p p q

So, we have:

$Pr = p*p*p*q$

$Pr = p^3*q$

$Pr = 0.60^3*0.40$

$Pr = 0.0864$

Solving (b): He closes for the first time on the 3rd attempt

This means that he fails to close the first two attempts. The event is represented as: q q p

So, we have:

$Pr = q * q * p$

$Pr = q^2 * p$

$Pr = 0.40^2 * 0.60$

$Pr = 0.096$

Solving (c): First he closes is his 2nd attempt

This means that he fails to close the first. The event is represented as: q p

So, we have:

$Pr = q * p$

$Pr = 0.40 * 0.60$

$Pr = 0.24$

Solving (d): The first he close is one of his 3 attempts

To do this, we make use of complement rule

The event that he does not close any of his first three attempts is: q q q

The probability is:

$Pr = q*q*q$

$Pr = q^3$

The opposite is that the first he closes is one of the first three

So, we have:

$Pr' = 1- Pr$ --- complement rule

$Pr' = 1- q^3$

$Pr' = 1- 0.40^3$

$Pr' = 1- 0.064$

$Pr' = 0.936$

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The first thing you should do is plot each region with respect to the temperature and then observe the behavior of each region.
Region A: not observable trend
Region B: exponential trend
Region C: negative linear trend
Region D: positive linear trend
Graphic attachment

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2 years ago

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Karo-lina-s [1.5K]

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2 years ago

If PQ=RS, which of the following must be true?

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<u>Answer:</u>

If PQ=RS then PQ and RS have the same length. Hence option D is correct

<u>Solution:</u>

Given that, pq = rs

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<u><em>a) pq and rs form a straight angle </em></u>

We can’t decide the angle in between pq and rs just by the statement pq = rs.

So this statement is false.

<u><em>b) pq and rs form a zero angle. </em></u>

We can’t decide the angle in between pq and rs just by the statement pq = rs.

So this statement is false.

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If two things equal then there is no condition that both represents a single item.

So this statement is false.

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As given that pq = rs, we can say that they will have the same length

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aliya0001 [1]

The perimeter of the original rectangle is:
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A = w * l = 250
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P '= 2 (2w) +2 (2l)
Rewriting:
P '= 2 (2w + 2l)
P '= 2P
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P '= 140
Area:
A '= (2w) * (2l)
Rewriting:
A '= (2) * (2) (w) * (l)
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Answer:
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