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2 years ago

Kohl's sells watches that cost $6.95 for a selling price of $39.99. What is the percent markup on cost?

1 answer:

Natasha2012 [34]2 years ago

3 0

We know that
A markup is the ratio of Gross Profit Margin to C<span>ost
</span>so
Markup Percentage = Gross Profit Margin/Unit Cost
Gross Profit Margin=Sales Price – Unit Cost------> $39.99-<span>$6.95----> $33.04
</span>Markup Percentage = $33.04/$6.95------> 4.7540------> 475.40%

the answer is
475.40%

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Find the area of irregular figure

elixir [45]

Step-by-step explanation:

For square

A=bh

A=30(20)

A=60in²

For triangle

A=½bh

A=½(40)(30)

A=½(120)

A=60in²

Add

60+60=120in²

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2 years ago

The graph shows the rate at which the depth of the water in a pond is changing over time. On a coordinate plane, a graph titled

lawyer [7]

Answer:

Step-by-step explanation:

The key to solving this question is to find the distance bwtween the two points given

distance=y2-y1/x2-x1

(2,4)(4,8)

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4=x2

8=y2

8-4/4-2

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1 year ago

Find a right triangle that has legs with your irrational Lengths and a hypotenuse with a rational Length

cluponka [151]

gg easy

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let's find some stuff

one easy way is to find a rational value for c find values of a and b

lets pick c=5

$a^2+b^2=5^2$

$a^2+b^2=25$

now split up 25 into 2 things that don't have rational square roots

if we say $a^2=19$ and $b^2=6$ then we get

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2 years ago

High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers

mamaluj [8]

Answer:

The 95% confidence interval the average maximum power is (596.0 to 644.0)

Step-by-step explanation:

Average maximum of the sample = x = 620 HP

Standard Deviation = s = 45 HP

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We have to calculate the 95% confidence interval. The value of Population standard deviation is unknown, and value of sample standard deviation is known. Therefore, we will use one sample t-test to build the confidence interval.

Degrees of freedom = df = n - 1 = 15

Critical t-value associated with 95% confidence interval and 15 degrees of freedom, as seen from t-table = $t_{\frac{\alpha}{2}}$ = 2.131