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attashe74 [19]
2 years ago
15

Courtney has a total of 88 stamps worth $15.56. Some are 25 cent stamps and some 2 cent stamps. How many of each does she have

Mathematics
2 answers:
Oksi-84 [34.3K]2 years ago
6 0
<span>88 stamps -------------------- >  $15.56
A------------------------------>number of  </span>stamps ------------ ><span>25 cent
B----------------------------- > </span>number of  stamps ------------ >2 cent

A+B=88------------------ > A=88-B
0.25A+.02B=15.56
resolving
0.25(88-B)+0.02B=15.56
22-0.25B+0.02B=15.56
-0.23B=-6.44----------------------- > B=28 stamps of 2 cent
A=88-B-- >88-28=60------------- > A=60 stamps of 25 cent
o-na [289]2 years ago
3 0

Answer: She has 68 25-cents stamps and 28 2-cents stamps.

Step-by-step explanation:

Let x be the number of 25 cents stamps and y be the number of 2 cents stamps.

Then According to the question  , we have

x+y=88.............(1)\\\\25x+2y=1556...................(2)

From (1), we have

y=88-x ...........(3)

Put value of y in (2), we get

25x+2(88-x)=1556\\\\\Rightarrow\ 25x+176-2x=1556\\\\\Rightarrow\ 23x=1556-176\\\\\Rightarrow\ 23x= 1380\\\\\Rightarrow\ x=\dfrac{1380}{23}=60

From (3), we have

y=88-60=28

Hence, she has 60 25 cent stamps and 28 2 cents stamps.

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One semester in a chemistry class, 14 students failed due to poor attendance, 23 failed due to not studying, 15 failed because t
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Answer:

(a) 16 students failed for exactly two of the three reasons.

(b) 7 students failed because of poor attendance and not studying but not because of not turning in assignments.

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(d) 3 students failed because of poor attendance and not turning in assignments but not because of not studying.

Step-by-step explanation:

We are given that one semester in a chemistry class, 14 students failed due to poor attendance, 23 failed due to not studying, 15 failed because they did not turn in assignments, 9 failed because of poor attendance and not studying, 8 failed because of not studying and not turning in assignments, 5 failed because of poor attendance and not turning in assignments, and 2 failed because of all three of these reasons.

As shown in the diagram attached below, a Venn diagram represents the situation given in the question;

In the diagram below, 2 in represents purple color represents the number of students failed because of all three of these reasons.

7 represents the number of students who failed because of poor attendance and not studying but not due to not turning in assignments.

6 represents the number of students who failed because of not studying and not turning in assignments but not due to poor attendance.

3 represents the number of students who failed because of poor attendance and not turning in assignments but not due to not studying.

2 in red color represents the number of students who failed only due to poor attendance.

8 in red color represents the number of students who failed only due to not studying.

4 in red color represents the number of students who failed only due to not turning in assignments.

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(b) The number of students who failed because of poor attendance and not studying but not because of not turning in assignments = 9 - 2 = 7 students.

(c) The number of students who failed because of exactly one of the three reasons = 2 + 8 + 4 = 14 students.

(d) The number of students who failed because of poor attendance and not turning in assignments but not because of not studying = 5 - 2 = 3 students.

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