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iogann1982 [59]
1 year ago
12

Your little brother has a a career batting average of 0.233. You want to determine the probability that he will have a batting a

verage of over 0.250 next season when he will be up to bat 40 times. Are the conditions met so that the sample proportion hatp will be approximately normal?
A. Yes. There is a large sample (n>30) so the sample proportion must be normal.
B. Yes. 40xx0.250>=10 so the conditions are satisfied.
C. No. hatp can only be normal if the sample data are normally distributed.
D. No. 40xx0.233<10 so the conditions are not satisfied.
Mathematics
1 answer:
alexandr402 [8]1 year ago
4 0

Answer:

b

Step-by-step explanation:

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Find the percentage change between two numbers if the original number was 150 and now is 330.
bearhunter [10]

Answer:

0.45

Step-by-step explanation:

8 0
2 years ago
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Write an expression that represents the volume of a rectangular prism (box) with length 2003-02-02-00-00_files/i0260000.jpg, wid
k0ka [10]

h=5 in

w-6 in

l=12 in

SA/V=2*12*6+2*6*5+2*12*5/12*6*5

817:180

This is just an example do not use this exact equation and number! Hope it helps. : )
3 0
1 year ago
Find the area of the part of the plane 5x + 4y + z = 20 that lies in the first octant.
BlackZzzverrR [31]
This part of the plane is a triangle. Call it \mathcal S. We can find the intercepts by setting two variables to 0 simultaneously; we'd find, for instance, that y=z=0 means 5x=20\implies x=4, so that (4, 0, 0) is one vertex of the triangle. Similarly, we'd find that (0, 5, 0) and (0, 0, 20) are the other two vertices.

Next, we can parameterize the surface by

\mathbf s(u,v)=\langle4(1-u)(1-v),5u(1-v),20v\rangle

so that the surface element is

\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|=20\sqrt{42}(1-v)\,\mathrm du\,\mathrm dv

Then the area of \mathcal S is given by the surface integral

\displaystyle\iint_{\mathcal S}\mathrm dS=20\sqrt{42}\int_{u=0}^{u=1}\int_{v=0}^{v=1}(1-v)\,\mathrm dv\,\mathrm du
\displaystyle=20\sqrt{42}\int_{v=0}^{v=1}(1-v)\,\mathrm dv=10\sqrt{42}\approx64.8074
3 0
2 years ago
A 15-inch candle is lit and steadily burns until it is burned out. Let b represent the burned length of the candle (in inches) a
hjlf

Answer:

(a)r=15-b

11.9 Inches

(b)See attached

Step-by-step explanation:

Length of the candle =15 inch

Let b represent the burned length of the candle (in inches)

Let r represent the remaining length of the candle (in inches).

Therefore:

(a) r+b=15

r=15-b

When b=3,1 Inches

Remaining Length, r=15-3.1=11.9 Inches

(b)The graph showing te relationship between r and b is shown below.

r is plotted on the y-axis while b is plotted on the x-axis as labelled.

5 0
2 years ago
The two-way frequency table below shows data on student behavior and the use of positive phone calls home as an incentive for go
dusya [7]

Answer:

From the frequency table, let's calculate the row total.

Row total for phone call = 19 + 9 = 28

Row total for no phone call = 8 +6 = 14

To calculate their respective row relative frequencies, let's use:

Row relative freq = \frac{freq.}{Row total}

Now, the two-way frequency table will be computed as:

For phone call:

Desirable behavior = \frac{19}{28} = 0.67857 ≈0.69

Undesirable behaviour = \frac{9}{28} = 0.3214 ≈0.32

No phone call:

Desirable behaviour = \frac{8}{14} = 0.5714 ≈ 0.57

Undesirable behaviour = \frac{6}{14} = 0.4286 ≈ 0.43

The complete two-way table is attached.

8 0
2 years ago
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