Given ED, DB which statements about the figure are true? Check all that apply.

Tom supports North Storm Football Club. At the match between North Storm and West Stanford there were 71,167 spectators. If 41,1

dangina [55]

Answer:
30,058 spectator

Explanation:
The total number of spectators is equal to the sum of West Stanford's and North Storm's supporters.
We are given that:
Total number of spectators = 71,167 spectator
North Storm spectators = 41,109 spectator
So, to get the number of West Stanford spectators, all we have to do is subtract North Storm spectators from the total spectators as follows:
West Stanford spectators = 71,167 - 41,109 = 30,058 spectator

Hope this helps :)

8 0

1 year ago

A mill processes 27 tons of flour in 3 hours. How many tons of flour can the mill process in 8 hours if the rate of production s

Delvig [45]

There are a few ways you can go about solving this question. One way is to use the given information to find how many tons of flour can be processed in one hour. If 27 tons can be processed in 3 hours, we can do 27 divided by 3 to find that 9 tons of flour can be processed per hour. Then, if we want to see how many tons of flour can be processed in 8 hours, we can multiply 9 tons by 8 hours to get a total of 72 tons of flour.

I hope this helps.

5 0

1 year ago

A student theater charges $9.50 per ticket. The theater has already sold 70 tickets. Write and solve an inequality that represen

Genrish500 [490]

9.50 times 70 is greater or less than 1000

8 0

1 year ago

What is the maximum vertical distance between the line y = x + 56 and the parabola y = x2 for −7 ≤ x ≤ 8?

atroni [7]

-7 and 8 are the solutions to the given equation system.
Therefore, the maximum distance between the y values of the two equations must lie exactly between their points of intersection. That is on x value:
x = (-7 + 8)/2 = 0.5
The maximum distance is:
y = 0.5 + 56 = 56.5
y = 0.5² = 0.25
56.5 - 0.25 = 56.25 units

5 0

1 year ago

A large manufacturing plant has analyzed the amount of time required to produce an electrical part and determined that the times

WARRIOR [948]

Answer:

We conclude that the new procedure will not decrease the population mean amount of time required to produce the part.

Step-by-step explanation:

We are given that a large manufacturing plant has analyzed the amount of time required to produce an electrical part and determined that the times follow a normal distribution with mean time μ = 45 hours.

A random sample of 25 parts will be selected and the average amount of time required to produce them will be determined. The sample mean amount of time is = 43.118 hours with the sample standard deviation s = 5.5 hours

Let $\mu$ = population mean amount of time required to produce an electrical part using new procedure

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 45 hours {means that the new procedure will remain same or increase the population mean amount of time required to produce the part}

Alternate Hypothesis, $H_a$ : $\mu$ < 45 hours {means that the new procedure will decrease the population mean amount of time required to produce the part}

The test statistics that will be used here is One-sample t test statistics because we don't know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{{\frac{s}{\sqrt{n} } } }$ ~ $t_n_-_1$

where, $\mu$ = sample mean amount of time = 43.118 hours

s = sample standard deviation = 5.5 hours

n = sample of parts = 25

So, test statistics = $\frac{43.118-45}{{\frac{5.5}{\sqrt{25} } } }$ ~ $t_2_4$

= -1.711

Now at 0.025 significance level, the t table gives critical value of -2.064 at 24 degree of freedom for left-tailed test. Since our test statistics is more than the critical value of t so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the new procedure will remain same or increase the population mean amount of time required to produce the part.

4 0

1 year ago