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Feliz [49]
2 years ago
6

A long time ago Dulani found an island shaped like a triangle with three straight shores of length 3 km 4 km and 5 km.He said no

body could come within 1km of his shore. What was the area of his exclusion zone?

Mathematics
1 answer:
VikaD [51]2 years ago
5 0
To find the area of his exclusion zone you would need to understand that a triangle with dimensions of 3, 4, and 5 represent a right triangle.

This means the exclusion zone would be applied to the base and the height of the triangular space.

You would add 2 km to the 3 km, and 2 km to the 4 km to create a new height of 5 km and a new base of 6 km.

Please see the attached picture to understand this.

You will find the area of the total space created by the new triangle and subtract the space represented by the original triangle to find the area of the exclusion zone.

(1/2 x 6 x 5) - (1/2 x 4 x 3)
15 km² -6 km² equals 9 km².

The exclusion space is 9 km².

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John and Belinda played a nine holes of golf. John's score was 10 less than two times Belinda's score. If Johns score was 54 str
polet [3.4K]

Answer:

Belinda's score is 32 strokes.

Step-by-step explanation:

Let the score of John be "x" and Belinda be "y".

It is given that, in the game of golf, John's score was 10 less than two times Belinda's score.

Also, John's score is 54 strokes.

The above equation can be written as ;

x = 2(y) -10

Here, x = 54,

54 = 2(y) -10

64 = 2(y)

y = 32

Thus, Belinda's score is 32 strokes.

6 0
2 years ago
Which of the following events are equal? (a) A = {1,3}; (b) B = {x | x is a number on a die }; (c) C = {x | x2 −4x +3=0 }; (d) D
rosijanka [135]

Answer:

A and C

Step-by-step explanation:

To determine which events are equal, we explicitly define the elements in each set builder.

For event A

A={1.3}

for event B

B={x|x is a number on a die}

The possible numbers on a die are 1,2,3,4,5 and 6. Hence event B is computed as

B={1,2,3,4,5,6}

for event C

C=[x|x^{2}-4x+3]\\solving  x^{2}-4x+3\\x^{2}-4x+3=0\\x^{2}-3x-x+3=0\\x(x-3)-1(x-3)=0\\x=3 or x=1

Hence the set c is C={1,3}

and for the set D {x| x is the number of heads when six coins re tossed }

In the tossing a six coins it is possible not to have any head and it is possible to have head ranging from 1 to 6

Hence the set D can be expressed as

D={0,1,2,3,4,5,6}

In conclusion, when all the set are compared only set A and set C are equal

5 0
2 years ago
Given your sister's incomplete text,
egoroff_w [7]

Explanation:

Quadrants 2 and 3 houses points that have negative x-values, while as Quadrants 1 and 4 houses points that have positive x-values.

If 'your sister' completes the text with negative y-value, the point would be in Q3.

If 'your sister' completes the text with positive y-value, the point would be in Q2.

8 0
2 years ago
Read 2 more answers
Ashley recently opened a store that uses only natural ingredients. She wants to advertise her products by distributing bags of s
Elenna [48]

I will rewrite the question for better understanding:

Ashley recently opened a store that uses only natural ingredients. She wants to advertise her products by distributing bags of samples in her neighborhood. It takes Ashley 2/3 of a minute to prepare one bag. It takes each of her friends 75% longer to prepare a bag. How many hours will it take Ashley and 4 of her friends to prepare 1575 bags of samples?

Answer:

  • <em><u>5.3 hours</u></em>

Explanation:

<u>1) Time it takes Ashley to preprate one bag: </u>

  • 2/3 min

<u>2) Time it takes each friend of Ashley: 75% more than 2/3 min</u>

  • 75% × 2/3 min = 0.75 × 2/3 min = 3/4 × 2/3 min= 2/4 min = 1/2 min = 0.5 min
  • 2/3 min + 1/2 min = 7/6 min

<u>3) Time it takes Ashley and the 4 friends working along to prepare one bag:</u>

  • Convert each time into a rate, since you can set that the total rate of Ashley along with her four friends is equal to the sum of each rate:

  • Rate of Ashley: 1 bag / (2/3) min = 3/2 bag/min

  • Rate of each friend: 1 bag / (7/6) min = 6/7 bag/min

  • Rate of Ashley and 4 friends = 3/2 bag/min + 4 × 6/7 bag/min = (3/2 +24/7) bag/min = 69/14 bag/min

<u>4) Time of prepare 1575 bags of samples:</u>

  • time = number of bags / number of bags per min = 1,575 bags / (69/14) bags/min = 319.56 min

<u>5) Convert minutes to hours:</u>

  • 356.56 min × 1 hour / 60 min = 5.3 hours
3 0
2 years ago
ALGEBRA Jake Duffy drove 12,568 miles
kirza4 [7]

Answer:

The cost per mile that Jack Duffy charge $0.278 per miles , i.e option B  

Step-by-step explanation:

Given as :

The distance drove by Jack Duffy = d = 12,568 miles

The fixed costs totaled = $1,485.00

The variable cost totaled = $2,015.75

Let The cost per mile that Jack Duffy charge = $x cost per miles

Now, According to question

The totaled cost = The fixed costs + The variable cost

Or, The totaled cost = $1,485.00 + $2,015.75

I.e  The totaled cost = $3500.75

Now,

The cost per mile that Jack Duffy charge = \dfrac{\extrm Total cost}{\textrm Total Distance}

I.e x = \dfrac{3500.75}{12568}

∴ x = $0.278 per miles

So,The cost per mile that Jack Duffy charge = x = $0.278 per miles .

Hence,The cost per mile that Jack Duffy charge $0.278 per miles , i.e option B  Answer

5 0
2 years ago
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