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Arte-miy333 [17]
2 years ago
15

Is 7.2 bigger than 7.21

Mathematics
2 answers:
Zepler [3.9K]2 years ago
6 0

Answer:

yes 7.2 is bigger than 7.21

Step-by-step explanation:

.2 is 2/10 and .21 is 21/100 which is much smaller that .2

Paraphin [41]2 years ago
4 0

Answer:

yes

Step-by-step explanation:

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Karl drove 617.3 miles. For each gallon of gas the car can travel 41 miles.Select a reasonable estimate of the number of gallons
zaharov [31]
Time for fractions!!!

I’m going to set a rate of miles per gallon and then cross multiply to get me answer.

41miles/gallon = 617.3/xgallons

617.3 multiplied by 1 and then divided by 41 = about 15.05 gallons

A reasonable estimate then is 15 and a half gallons, because rather than measuring down to the hundredths, the next closest and reasonable measurement is 15 and a half or under.

Comment if you don’t understand and I’ll try to help.

5 0
2 years ago
The sales data for January and February of a frozen yogurt shop are approximately normal. The mean daily sales for January was $
VashaNatasha [74]

Answer:

January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.

Step-by-step explanation:

z-score:

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

January:

The mean daily sales for January was $300 with a standard deviation of $20. On the 15th of January, the shop sold $310 of yogurt. This means, respectively, that \mu = 300, \sigma = 20, X = 310. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{310 - 300}{20}

Z = 0.5

February:

The mean daily sales for February was $320 with a standard deviation of $50. On the 15th of February, the shop sold $340 of yogurt. This means, respectively, that \mu = 320, \sigma = 50, X = 340. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{340 - 320}{50}

Z = 0.4

January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.

3 0
2 years ago
Kieran subscribes to a text messaging service on his cell phone. His monthly bill for the service is given by the equation b = 0
Marina CMI [18]
B=kt
constant is k
b=0.25t

constant of proprtionality is 0.25
3 0
2 years ago
Read 2 more answers
in germany, VAT is at 19% Jeremy buys a calculator in germny for €58.31 This price includes VAT Find the amount of VAT paid by
Len [333]

We can use this equation to solve this problem:

<span>t=p+<span>(p⋅r)</span></span>

Where:

t is the total price paid: 58.31 for this problem

p is the price before taxes: What we are solving for in this problem.

r is the tax or VAT rate: 19% for this problem. "Percent" or "%" means "out of 100" or "per 100", Therefore 19% can be written as <span>19100</span> or 0.19.

Substituting and solving for p gives:

<span>58.31=p+<span>(p⋅0.19)</span></span>

<span>58.31=1p+0.19p</span>

<span>58.31=<span>(1+0.19)</span>p</span>

<span>58.31=1.19p</span>

<span><span>58.311.19</span>=<span><span>1.19p</span>1.19</span></span>

<span>49=<span><span>1.19p</span>1.19</span></span>

<span>49=p</span>

<span>p=49</span>

Now, we can find how much the VAT was by taking 19% of 49:

<span>19%×49=0.19×49=9.31</span>

Another was to solve this is to subtract the price without the tax or VAT from the total price giving:

<span>58.31−49=<span>9.31</span></span>

4 0
2 years ago
Read 2 more answers
Find the interest due to the bank on a loan of $1000 at 7.5% for 280 days
Lera25 [3.4K]

Answer:

The interest is \$57.53

Step-by-step explanation:

we know that

The simple interest formula is equal to

I=P(rt)

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

t=280/365\ years\\ P=\$1.000\\r=0.075

substitute in the formula above

I=\$1.000(0.075*280/365)

I=\$57.53

7 0
2 years ago
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