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Andru [333]
2 years ago
7

Kimberly is considering buying her first home. The house she is interested in buying is priced at $159,000. Kimberly qualifies f

or a 30-year mortgage at 4.75%. What will be her monthly mortgage payment?
Mathematics
2 answers:
lbvjy [14]2 years ago
8 0
829.00    I just used a mortgage calculator 
Grace [21]2 years ago
5 0
I think it's $829.00 but you can always work it out and check it. :)
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Diego's sister is twice his age minus 9 years. She is also as old as half the sum of the ages of Diego and both of his 12-year-o
slava [35]

Answer:

Diego is 14 years old.

Sister is 19

Step-by-step explanation:

x = Diego's age

<u>x</u><u> </u><u>+</u><u> </u><u>2</u><u>4</u>

2x-9 = 2

First to get rid of the fraction we multiply each side by 2

2(2x-9) = 2((x+24)/2)

4x-18 = x+24

The we isolate x

4x-18 = x+24

<u>-x+18 -x+18</u>

<u>3x</u> = <u>42</u> Now we divide each side 3

3 3

x = 14

So Diego is 14

Now we can solve for his sister. We can use one of the two equations from earlier to do this.

Plug 14 in for x and then solve for his sister

2(14)-9

28-9

19

His sister is 19

5 0
2 years ago
Read 2 more answers
The scatter plot shows the number of text messages sent per day versus age (in years) of the smartphone user.
Ghella [55]

Answer: find the answers in the explanation.

Step-by-step explanation:

Given that the predicted Number of Text Messages Sent = 60 – 0.8 • Age

Where the slope = - 0.8

The intercept = 60

1) the slope of the least regression line is -0.8

2.) The unit of the slope of the line is text per year

3.) Therefore, the slope of the line tells you that for every year older the smart phone user is, you can expect a typical average in text messages sent of - 0.8

4.) The y - intercept of the least square regression line is 60

5.) The unit of the y - intercept of the line are text sent

6.) The y - intercept of the line tells you the starting point. The first number of text messages sent.

4 0
2 years ago
Niki makes the same payment every two months to pay off his $61,600 loan. The loan has an interest rate of 9.84%, compounded eve
mars1129 [50]
After a series of calculations, I found out that the interest he has to pay in total would be <span>$117,484.77.

You might use my answer in reviewing by using your solution also.

I hope my answer has come to your help. God bless and have a nice day ahead!
</span>
6 0
2 years ago
Read 2 more answers
Really important please help #8
Paladinen [302]
B is the answer! Enjoy getting it correct!! :)
5 0
2 years ago
Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
2 years ago
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