Really important please help #8

A composition of transformations ΔKLM maps ΔK"L"M" to . Triangle K L M is rotated 270 degrees about point P to form Triangle K p

telo118 [61]

Answer:

a 270° rotation about point P

Step-by-step explanation:

Because after transformation MK and M'K 'are at 90°, that implies that MK is rotated as 90 ° clockwise around P or 270 ° counterclockwise around P.

Therefore the transformation composition that maps $\triangle KLM$ to $\triangle$ K"L"M",

So, for this composition, the first transformation is 270° is the 270° rotation i.e to be counterclockwise about point P.

While the transformation of the second would be down translation that goes to the right.

hence, the last option is correct

6 0

2 years ago

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In the diagram, P1P2 and Q1Q2 are the perpendicular bisectors of line AB and BC , respectively. A1A2 and B1B2 are the angle bise

Aliun [14]

I hope I can show the image, but I hope this may help you, the answer is:

The center of the inscribed circle of ΔABC is <u>point S</u> , and the center of the circumscribed circle of ΔABC is <u>point P.</u>

4 0

2 years ago

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A company purchased a delivery van for $28,000 with a salvage value of $3,000 on September 1, Year 1. It has an estimated useful

Tems11 [23]

Answer:

Depreciation till December 31, Year 1 will be equal to 1,250$

Step-by-step explanation:

Purchasing Cost = 28,000$

Salvage Value = 3,000$

Total Depreciation:

Total Depreciation over 5 years (60 Months) = Purchasing Cost - Salvage Value

Total Depreciation over 5 years (60 Months) = 28,000 - 3,000

Total Depreciation over 5 years (60 Months) = 25,000$

Monthly Depreciation:

Using the unity method we have monthly depreciation by dividing the total depreciation by the total no. of months as below:

Total Depreciation over a single month =25,000/60

Total Depreciation over a single month = 416.67$ (Monthly Depreciation)

Depreciation till December 31, Year 1

As from September 1, Year 1 to December 31, Year 1, its been 3 months therefore total depreciation will be = 3 * Monthly Depreciation

Depreciation till December 31, Year 1 = 3 * 416.67

Depreciation till December 31, Year 1 = 1,250$

4 0

1 year ago

Find the first three iterates of the function f(z) = 2z + (3 - 2i) with an initial value of

nikklg [1K]

Answer:

a. 5 + 2i, 13 + 2i, 29 + 2i

Step-by-step explanation:

We'll use the formula f(z) = 2z + (3 - 2i) for each iteration. The output of the first iteration will be come the input of the second iteration, and so on.

So, we start with z0 = 1 + 2i and we plug that into the base equation:

z0 = 1 + 2i ==> f(z) = 2(1 + 2i) + 3 - 2i = 2 + 4i + 3 - 2i = 5 + 2i

z1 = 5 + 2i ==> f(z) = 2(5 + 2i) + 3 - 2i = 10 + 4i + 3 - 2i = 13 + 2i

z2 = 13 + 2i ==> f(z) = 2(13 + 2i) + 3 - 2i = 26 + 4i + 3 - 2i = 29 + 2i

z3 = 29 + 2i

8 0

1 year ago

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The average cost of gas where you live is $3.50 per gallon, you are trying to decide whether to buy a hybrid or standard car. Th

Paladinen [302]

Answer:

Step-by-step explanation: