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1 year ago

Really important please help #8

Mathematics

1 answer:

Paladinen [302]1 year ago

5 0

B is the answer! Enjoy getting it correct!! :)

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Cindy found a collection of baseball cards in her attic worth $8,000. the collection is estimated to increase in value by 1.5% p

Sergio [31]

A]
Exponential function is given by the form:
y=a(b)ˣ
where:
a=initial value
b=growth factor
From the question:
a=$8000, b=1.015,
thus the exponential growth function of this situation is:
y=8000(1.015)ˣ

b] The value of the collection after 7 years will be:
x=7 years
Using the formula:
y=8000(1.015)ˣ
plugging the values we get:
y=8000(1.015)⁷
y=8,878.76

Answer: $8,878.76

7 0

1 year ago

The heights of fully grown sugar maple trees are normally distributed, with a mean of 87.5 feet and a standard deviation of 6.25

Julli [10]

Answer:

20.33%

Step-by-step explanation:

We have that the mean (m) is equal to 87.5, the standard deviation (sd) 6.25 and the sample size (n) = 12

They ask us for P (x <86)

For this, the first thing is to calculate z, which is given by the following equation:

z = (x - m) / (sd / (n ^ 1/2))

We have all these values, replacing we have:

z = (86 - 87.5) / (6.25 / (12 ^ 1/2))

z = -0.83

With the normal distribution table (attached), we have that at that value, the probability is:

P (z <-0.83) = 0.2033

The probability is 20.33%

6 0

1 year ago

What is the product? (-2x-9y^2)(-4x-3)

telo118 [61]

Answer:-8x^2-6x+36xy^2+27y^2

Step-by-step explanation:

using the FOIL method

6 0

2 years ago

Read 2 more answers

A medication states that the odds of having an allergic reaction are 1 in 50. What is that probability states as a percent?

kicyunya [14]

Answer: 2%, second option is correct.

Step-by-step explanation:

To state 1/50 in percent, divide 1 by 50, then multiply by 100

=( 1 ÷ 50) x 100

= 0.02 x 100

= 2%

I hope this helps, please mark as brainliest.

5 0

1 year ago

For a recent season in college football, the total number of rushing yards for that season is recorded for each running back. Th

Galina-37 [17]

Answer:

The standard deviation of the number of rushing yards for the running backs that season is 350.

Step-by-step explanation:

Consider the provided information.

The mean number of rushing yards for the running backs that season is 790 yards. One running back had 1,637 rushing yards for the season, which is 2.42 standard deviations above the mean number of rushing yards.

Here it is given that mean is 790 and 1637 is 2.42 standard deviations above the mean.

Use the formula: $z=\frac{x-\mu}{\sigma}$

Here z is 2.42 and μ is 790, substitute the respective values as shown.

$2.42=\frac{1637-790}{\sigma}$

$\sigma=\frac{847}{2.42}$

$\sigma=350$

Hence, the standard deviation of the number of rushing yards for the running backs that season is 350.

4 0

2 years ago