All categories

2 years ago

It takes 45 minutes to drive to the nearest bowling alley taking city streets going

Mathematics

1 answer:

Savatey [412]2 years ago

7 0

Answer:

21 minutes

Step-by-step explanation:

Given the following :

Taking CITY STREET:

Time taken to drive to nearest bowling alley = 45 minutes = 45/60 = 0.75 hours

Speed of travel = 30 miles per hour

Taking FREEWAY:

speed of travel = 65miles per hour

If the distance to bowling alley is the same along both routes, The time taken along FREEWAY will be :

Distance to bowling alley taking city center :

Speed = distance / time

30 mph = distance / 0.75 hour

Distance = 30 × 0. 75 = 22.5 miles

Since distance is the same :

Time taken along FREEWAY :

Time taken = distance / speed

Time taken = 22.5 / 65 = 0.3461538 hour

Converting to minutes :

0.3461538 × 60 = 20.769 minutes

= 21 minutes ( to the nearest minute)

You might be interested in

$24 saved after 3 weeks; $52 saved after 7 weeks. are these ratios equivalent

SIZIF [17.4K]

To figure out this question, I first divided 24 into 3, which gives me an answer of 8. then I divided 52 into 7 , which also is 8 . because the two numbers are the same, I know the ratios are equivalent.

4 0

2 years ago

Read 2 more answers

A person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed, t

maksim [4K]

Answer:

Boat traveled 553.24 feet towards the lighthouse.

Step-by-step explanation:

In the figure attached AB is the light house of height 200 feet.

Angle of depression of the boat from the top of a lighthouse = angle of elevation of the lighthouse from the boat = 14°52'

so 1' = $\frac{1}{60}$ degree

so angle of elevation at point C = 14 + $\frac{52}{60}$

So angle of elevation from C = (14 + 0.87) = 14.87°

Similarly, when boat arrives at point D angle of elevation = 45°10' = 45 + $\frac{10}{60}$ = 45.17°

Now we have to calculate the distance CD, traveled by the boat.

In ΔABC

tan14.87 = $\frac{200}{BC}$

0.2655 = $\frac{200}{BC}$

BC = $\frac{200}{0.26552}$

BC = 753.239 feet

Similarly in ΔABD

tan45.17 = $\frac{200}{BD}$

1 = $\frac{200}{BD}$

BD = 200 feet

So distance CD = BC - BD

CD = 753.239 - 200

= 553.24 feet

Therefore, Boat traveled 553.24 feet towards the lighthouse.

7 0

2 years ago

Read 2 more answers

A local high school held a two-day fundraiser selling lunches. The equations shown represent the amount of money the school coll

Likurg_2 [28]

It will be a kid getting hit in the leg by the kids in the lunch table so it will be 4

5 0

2 years ago

Mr. Peterson needs topsoil for his garden. His rectangular garden is 78 in long and 48 in wide. A bag of topsoil covers an area

nata0808 [166]

Answer:

3744 inches squared, and 8 bags

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

˜”*°•.˜”*°• Area: •°*”˜.•°*”˜

Well, the formula for area is L*W

L=78 inches

W=48 inches

78*48=3744 inches squared

˜”*°•.˜”*°• Number of bags: •°*”˜.•°*”˜

3744/500=7.448

So he would need to buy 8 bags

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

4 0

1 year ago

Suppose that water is pouring into a swimming pool in the shape of a right circular cylinder at a constant rate of 8 cubic feet

adell [148]

Answer:

dh/dt = 0,07 ft/min

Step-by-step explanation:

The swimming pool has the shape of right circular cylinder, therefore its volume is

V(c) = π*x²*h

Where x is the radius of the base and h the height

We take differentiation on both sides of the equation to get:

dV/dt = π*x²*dh/dt

The rate of change in height of water in the pool, is independent of the height of the water, since the pool is a right crcular cylinder, and dV/dt is constant at 8 ft³/min.

Then:

8 = π*x²*dh/dt

dh/dt = 8 / π*x²

dh/dt = 8/113,04

dh/dt = 0,07 ft/min

7 0

2 years ago