Step-by-step explanation:
The simplest method is "brute force". Calculate each term and add them up.
∑ = 3(1) + 3(2) + 3(3) + 3(4) + 3(5)
∑ = 3 + 6 + 9 + 12 + 15
∑ = 45
∑ = (2×1)² + (2×2)² + (2×3)² + (2×4)²
∑ = 4 + 16 + 36 + 64
∑ = 120
∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)
∑ = -4 + -2 + 0 + 2
∑ = -4
4. 1 + 1/4 + 1/16 + 1/64 + 1/256
This is a geometric sequence where the first term is 1 and the common ratio is 1/4. The nth term is:
a = 1 (1/4)ⁿ⁻¹
So the series is:
5. -5 + -1 + 3 + 7 + 11
This is an arithmetic sequence where the first term is -5 and the common difference is 4. The nth term is:
a = -5 + 4(n−1)
a = -5 + 4n − 4
a = 4n − 9
So the series is:
Answer:
The inverse is ±sqrt((x-1))/ 4
Step-by-step explanation:
y = 16x^2 + 1
To find the inverse, exchange x and y
x = 16 y^2 +1
Then solve for y
Subtract 1
x-1 = 16 y^2
Divide by 16
(x-1)/16 = y^2
Take the square root of each side
±sqrt((x-1)/16) = sqrt(y^2)
±sqrt((x-1))/ sqrt(16) = y
±sqrt((x-1))/ 4 = y
The inverse is ±sqrt((x-1))/ 4
Answer:
Answer is, 26.4
Step-by-step explanation:
By subtracting 51.82 by 26.37, you're left with a total of 26.37, and by rounding that to the tenths place, you get 26.4
The is Answer:
82
Explanation:
We observe that difference between first and second terms <span>=12−5=7</span>
Similarly difference between second and third terms <span>=19−12=7</span>
It shows that the given sequence of numbers is an arithmetic progression with common difference equal to 7.
We know that <span>nth</span> term of an AP whose first term is <span>a1</span> and whose common difference is d is given by
<span><span>an</span>=<span>a1</span>+<span>(n–1)</span>d</span>
To find the <span>12th</span> term, insert given values in the general expression
<span><span>a12</span>=5+<span>(12–1)</span>7</span>
<span><span>a12</span>=5+<span>(11)</span>7=5+77=<span>82</span></span>
Answer:
Step-by-step explanation:
The multiples of numbers calculator will find 100 multiples of a positive integer. For example, the multiples of 3 are calculated 3x1, 3x2, 3x3, 3x4, 3x5, etc., which equal 3, 6, 9, 12, 15, etc. You can designate a minimum value to generate multiples greater than a number.
