All categories

2 years ago

If the third term in an arithmetic sequence is 7 and the common difference is -5, what is the value of the fourth term?

Mathematics

2 answers:

baherus [9]2 years ago

5 0

Answer: 12 would be your answer.

Step-by-step explanation:

pochemuha2 years ago

4 0

The is Answer:

Explanation:

We observe that difference between first and second terms =12−5=7
Similarly difference between second and third terms =19−12=7

It shows that the given sequence of numbers is an arithmetic progression with common difference equal to 7.

We know that nth term of an AP whose first term is a1 and whose common difference is d is given by
an=a1+(n–1)d

To find the 12th term, insert given values in the general expression
a12=5+(12–1)7
a12=5+(11)7=5+77=82

You might be interested in

What is 15 tens - 1 gross

vampirchik [111]

Answer:

see the explanation

Step-by-step explanation:

we know that

A gross is equal to 120 ones or ten dozen

what is 15 tens - 1 gross

we know that

15 tens means ----> That you are adding 10, 15 times or multiplying 10 by 15, which gives you

$10(15)=150$

1 gross means ---> That you are adding 10, 12 times or multiplying 10 by 12

which gives you

$10(12)=120$

The algebraic expression of 15 tens - 1 gross is equal to

$150-120=30$

Convert to word expression

3 tens

8 0

1 year ago

1. A person owns a collection of 30 CDs, of which 5 are country music. If 2 CDs are selected at

OverLord2011 [107]

Answer:

Step-by-step explanation:

Sunflower can u please come answer my question next it says

HELP ASAP WILL GIVE BRAINLIEST PLEASE IM DESPERATE!!!!!!!

5 0

1 year ago

Read 2 more answers

4. Hydrocarbons in the cab of an automobile were measured during trips on the New Jersey Turnpike and trips through the Lincoln

pochemuha

Answer:

No these these result do not differ at 95% confidence level

Step-by-step explanation:

From the question we are told that

The first concentrations is $c _1= 30.0 \ g/m^3$

The second concentrations is $c _2 = 52.9 \ g/m^3$

The first sample size is $n_1 = 32$

The second sample size is $n_2 = 32$

The first standard deviation is $\sigma_1 = 30.0$

The first standard deviation is $\sigma_1 = 29.0$

The mean for Turnpike is $\= x _1 = \frac{c_1}{n} = \frac{31.4}{32} = 0.98125$

The mean for Tunnel is $\= x _2 = \frac{c_2}{n} = \frac{52.9}{32} = 1.6531$

The null hypothesis is $H_o : \mu _1 - \mu_2 = 0$

The alternative hypothesis is $H_a : \mu _1 - \mu_2 \ne 0$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} }}$

$t = \frac{0.98125 - 1.6531}{ \sqrt{\frac{30^2}{32} +\frac{29^2}{32} }}$

$t = - 0.0899$

Generally the degree of freedom is mathematically represented as

$df = 32+ 32 - 2$

$df = 62$

The significance $\alpha$ is evaluated as

$\alpha = (C - 100 )\%$

=> $\alpha = (95 - 100 )\%$

=> $\alpha =0.05$

The critical value is evaluated as

$t_c = 2 * t_{0.05 , 62}$

From the student t- distribution table

$t_{0.05, 62} = 1.67$

$t_c = 2 * 1.67$

=> $t_c = 3.34$

given that

$t_c > t$ we fail to reject the null hypothesis so this mean that the result do not differ

6 0

1 year ago

Six identical square pyramids can fill the same volume as a cube with the same base. If the height of the cube is h units, what

Rus_ich [418]

Answer:

I believe "The height of each pyramid is one-half h units"

4 0

1 year ago

Read 2 more answers

In a class of 20 students, 7 were wearing a white shirt. In the same class, 14 students had on blue jeans. Eyewitnesses all stat

nadezda [96]

Answer:

I want to answer 15%

Step-by-step explanation:

As for how to solve it I don't really know I would use process of elimination because the answer can't be so high that it's 45% so that's out. Personally I think that 35% is pretty high to so my best educated guess would be between 25% and 15% . Sorry this isn't more helpful.

6 0

2 years ago