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Oxana [17]
1 year ago
7

If the third term in an arithmetic sequence is 7 and the common difference is -5, what is the value of the fourth term?

Mathematics
2 answers:
baherus [9]1 year ago
5 0

Answer: 12 would be your answer.

Step-by-step explanation:

pochemuha1 year ago
4 0
The is Answer:

82

Explanation:

We observe that difference between first and second terms <span>=12−5=7</span>
Similarly difference between second and third terms <span>=19−12=7</span>

It shows that the given sequence of numbers is an arithmetic progression with common difference equal to 7.

We know that <span>nth</span> term of an AP whose first term is <span>a1</span> and whose common difference is d is given by 
<span><span>an</span>=<span>a1</span>+<span>(n–1)</span>d</span>

To find the <span>12th</span> term, insert given values in the general expression
<span><span>a12</span>=5+<span>(12–1)</span>7</span>
<span><span>a12</span>=5+<span>(11)</span>7=5+77=<span>82</span></span>

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In the problem it is already given that Weston Laundry washed 285.38 pounds of towel and 353.47 pounds of sheets from local hotels in 1 day. Firstly we have to find the total pounds of linens that Weston Laundry has washed in 7 days. Then only will it be possible to find the amount of linen washed in a day.
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Then
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4 0
1 year ago
ken purchased a plot of land shaped like the figure shown. how can he find the length of the side labeled x if he knows the area
OLga [1]
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1 year ago
Two quadrilaterals are congruent. One has vertices P, N, O, and M, and the other has vertices S, T, V, and U. These correspondin
Bogdan [553]

Answer: NPOM \cong VUTS and OPNM \cong TVUS will be correct.

Explanation:

Given: two quadrilaterals having verticals P, N, O,M and S,T,V,U are congruent,  where, OM is congruent or equal to TS and \angle P\cong \angle U.

in quadrilaterals NPOM and  VUTS-

since, the condition \angle P = \angle U

and, side UV=side  OM   follow for the above quadrilateral. (According to the figure)

then we can say according to the property of quadrilateral, their corresponding sides must be congruent. so they are congruent.

similarly, these two conditions also follow in the case of OPNM \cong TVUS

we can understand it by making the figures.


6 0
1 year ago
Read 2 more answers
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Verdich [7]
Eric need 5 batches of paving stones to created his patio.
6 0
1 year ago
Find the eccentricity, b. identify the conic, c. give an equation of the directrix, and d. sketch the conic.
densk [106]

Answer:

a) 10/3  

b) hyperbola

c) x = ± 6/5

Step-by-step explanation:

a) A conic section with a focus at the origin, a directrix of x = ±p where p is a positive real number and positive eccentricity (e) has a polar equation:

r=\frac{ep}{1\pm e*cos\theta}

Given the conic equation: r=\frac{12}{3-10cos\theta}

We have to make it to be in the form r=\frac{ep}{1\pm e*cos\theta}:

r=\frac{12}{3-10cos\theta}\\\\multiply\ both\ sides\ by\ \frac{1}{3} \\\\r=\frac{12*\frac{1}{3}}{(3-10cos\theta)*\frac{1}{3}}\\\\r=\frac{12*\frac{1}{3}}{3*\frac{1}{3}-10cos\theta*\frac{1}{3}}\\\\r=\frac{4}{1-\frac{10}{3}cos\theta } \\\\r=\frac{\frac{10}{3}(\frac{6}{5} ) }{1-\frac{10}{3}cos\theta }

Comparing with  r=\frac{ep}{1\pm e*cos\theta}

e = 10/3 = 3.3333, p = 6/5

b) since the eccentricity = 3.33 > 1, it is a hyperbola

c) The equation of the directrix is x = ±p = ± 6/5

6 0
1 year ago
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