6p=13.50
there are 6 notebooks and it costs $13.50 altogether. P represents the cost of one notebook, therefore the equation would be 6p=13.5. It can be rearranged to p=13.5/6
Answer:
0.0359
Step-by-step explanation:
Data provided:
mean values of three independent times are 15, 30, and 20 minutes
the standard deviations are 2, 1, and 1.6 minutes
Now,
New Mean = 15 + 30 + 25 = 65
Variance = ( standard deviation )²
or
Variance = 2² + 1² + 1.6² = 7.56
therefore,
Standard deviation = √variance
or
Standard deviation = 2.75
Thus,
Z-value = 
or
Z-value = - 1.81
from the Z-table
the Probability of Z ≤ -1.81 = 0.0359
Answer:
D. There is not enough evidence at the 5% significance level to indicate that one route gets Katy to work faster, on average, since 0 falls within the bounds of the confidence interval.
Step-by-step explanation:
At 5% confidence level, Katy found difference in mean commuting times (Route 1-Route 2) in minutes as (-1,9).
Since no difference in means (0 min) falls within the confidence level (-1,9), we can not reject the hypothesis that there is no difference in mean commuting times when using Route1 or Route2.
A <em>higher</em> significance level(10% etc) may lead a <em>shorter</em> confidence interval leaving 0 outside and may reach a conclusion that Route1 takes longer than Route2
Product means multiplication.
Given w= weight of a trout.
So, we need to convert "product of 16 and weight of trout: w " into an algebraic expression.
So, product of 16 and w can be written as 16*w or simply 16w.
Hence, B is the correct choice.
S=small pizzas
p=pasta dinners
s+p=1600
9s+13p=15600
multiply first equaiton by -9 and add to the second one
-9s-9p=-14400
<u>9s+13p=15600 +</u>
0s+4p=1200
4p=1200
divide by 4
p=300
sub back
s+p=1600
s+300=1600
minus 300 both sides
s=1300
1300 small pizzas
300 pasta dinners