The answer to the question above as to which system of equations can be used to model the situation of Graham and Hunter when a cable lifts Graham into the air at a speed of 1.5 ft/s and Hunter throws the ball from a position of 5 ft. above the ground with an initial velocity of 24 ft/s. the equation will be : H = 18t + 1.5t - 16t ^ 2
H = 5 + 24t - 16t ^ 2
7:15-7:20 is 5 minutes
If every one minute is 11 units then it would be 5x11=55
If it was at point 100 it would now be at point 100+55=155
Answer: point 155
Hope this is correct and helps :)
I hope this helps you
x.3x+x.(-1)+5.3x+5.(-1)-(x^2-2.4.x+16)
3x^2-x+15x-5-x^2+8x-16
2x^2+22x-21
1. Zoe stacked the most brownies. She stacked 27 brownies out of the 50 brownies.
2. 15
3. 43 + 3n ≥ 70, so n ≥ 9
4. D. 58x + 13 + 58y
5. The answer would be ≤4
6. 9.94 + 10.01p ≤ 70, so p ≤ 6
7. C 40 89
8. D. x+(x+5)=77
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We know, acceleration = change in speed / time
a = (3.5 - 3.1) / 15
a = 0.4 / 15
a = 0.026 m/s²
In short, Your Answer would be: 0.026 m/s²
Hope this helps!
