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marta [7]
1 year ago
15

Devin brought his snail collection to school. He has 10 snails. How could he put them into 2 tanks so two classes could see them

?
Mathematics
2 answers:
AlexFokin [52]1 year ago
8 0

Answer: Put 5 in each tank

Step-by-step explanation:

SVEN [57.7K]1 year ago
5 0
He could put 5 in each
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A 6 inch-tall plant grew 3/4 of an inch week and twice as much the following week. How tall is the plant now?
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8.25 inches once you multiply the 3/4 by 2 and add that and also add the 3/4 from the previous week you’ll get your answer
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1 year ago
If mBC = (9x-53) and mCD = (2x + 45) find mBAD
Rom4ik [11]

Answer:

m\angle BAD=73^o

Step-by-step explanation:

The picture of the question in the attached figure

step 1

Find the value of x

Let

O ----> the center of the circle

we know that

Triangle BOC≅Triangle COD

m\angle BOC=arc\ BC ----> by central angle

m\angle COD=arc\ CD ----> by central angle

m\angle BOC=m\angle COD

therefore

arc\ BC=arc\ CD

substitute the given values

(9x-53)^o=(2x+45)^o

solve for x

9x-2x=45+53\\7x=98\\x=14

step 2

Find the measure of angle BAD

we know that

The inscribed angle is half that of the arc it comprises.

so

m\angle BAD=\frac{1}{2} [arc\ BC+arc\ CD]

arc\ BC=9(14)-53=73^o

arc\ CD=2(14)+45=73^o

substitute

m\angle BAD=\frac{1}{2} [73^o+73^o]=73^o

7 0
1 year ago
Mrs Atkins is going to choose two students from her class to take part in a competition.
Schach [20]

Given:

Total number of girls in her class = 16

Total number of boys in her class = 14

To find:

The number of different ways of choosing one girl and one boy.

Solution:

We have,

Total number of girls = 16

Total number of boys = 14

So,

Total number of ways to select one girl from 16 girls = 16

Total number of ways to select one boy from 14 boys = 14

Now, number of different ways of choosing one girl and one boy is

16\times 14=224

Therefore, the required number of different ways is 224.

6 0
2 years ago
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