Maya can run 18 miles in 3 hours, and ahe can bike 18 miles in 2 hours.

A campus deli serves 300 customers over its busy lunch period from 11:30 am to 1:30 pm. A quick count of the number of customers waiting in line and being served by the sandwich makers shows that an average of 10 customers are in process at any point in time. What is the average amount of time that a customer spends in process?

Answer:

4 minutes

Step-by-step explanation:

For this question, we will apply Little's law which is is a theorem that determines the average number of items in a stationary queuing system, based on the average waiting time of an item within a system and the average number of items arriving at the system per unit of time.

The formula for the law is:

Inventory = flow rate × flow time.

We are given;

Inventory = 300 customers

flow time is from 11: 30am to 1:30pm which is 2 hours = 120 minutes

Flow rate = 300/120 = 2.5 persons/minute

Now, Making flow rate the subject of the formula earlier given, we have;

flow rate = inventory/ flow time

Flow time is the time each person spends in the process

Thus, plugging in the relevant values, we get ;

We are told that an average of 10 customers are in process at any point in time.

Thus;

Average flow time = average inventory/flow rate = 10/2.5 = 4 minutes

3 0

2 years ago

An airplane travels at 950 km/h. how long does it take to travel 1.00km? in hours

Kay [80]

An airplane travels at 950 km/h. how long does it take to travel 1.00km? in hours, 0.0010526 hrs.

6 0

2 years ago

A group of college DJs surveyed students to find out what music to plan for their upcoming parties. Thirty percent of the studen

Sindrei [870]

Answer:

A - The proportion of students that like trance music but not dubstep is 10%

B - The proportion of students that like either dubstep or trance is 40%

C - The proportion of students that like neither trance music nor dubstep is 60%

D - The proportion of students that didn’t select any of the music options available on the survey was 40%

E - The proportion of students that preferred either dubstep or trance is calculated by: P(D) + P(T) - P(D and T)

F - The conditional probability that a student likes dubstep, given that he or she likes trance music, is 60%

Step-by-step explanation:

P(D)=the students preferred dubstep=30%

P(T)=the students selected trance music=25%

P(H)=the students selected house music=20%

P(D and T)=the students liked both dubstep and trance=15%

A - The proportion of students that like trance music but not dubstep is:

P(T) - P(D and T)=25%-15%=10%

B - The proportion of students that like either dubstep or trance is:

P(D) + P(T) - P(D and T) =30%+25%-15% = 40%

C - The proportion of students that like neither trance music nor dubstep is

100% - (P(D) + P(T) - P(D and T) ) =60%

D - The proportion of students that didn’t select any of the music options available on the survey was:

100% - (P(H)+P(D) + P(T) - P(D and T) ) =40%

F - The conditional probability that a student likes dubstep, given that he or she likes trance music, is:

$\frac{P(D and T)}{P(T)}$ = $\frac{0.15}{0.25} =0.60$

6 0

2 years ago