Answer:
11 boxed lunches
Step-by-step explanation:
Full question
Janie ordered boxed lunches for a student advisory committee meeting. Each lunch cost 4.25. The total cost of the lunches is 53.75, including a 7$ delivery fee. Write and solve an equation to find x the number of boxed lunches Janie ordered
First of all subtract the delivery feesince it was inckuded in the total cost, this will now be the total cost of all the noxed lunches ordered by Janie, then divide the balance of the total cost by the cost of one boxed lunch to get thd total boxed kunches
X= 53.75-7/4.25
X= 53.75-7= 46.75/4.25
X=11
A) 3x100= 300 since figure 1 is 3 then figure 100 is 3x100
Answer:
The amount of soup the can will hold is;
50π inches cubed = 157.08 inches cubed
Step-by-step explanation:
The amount of soup the can will hold is equal to the volume of the can.
Volume of the can = base area × height
Given;
Base Area = 5π inches squared
height = 10 inches
Volume of can = 5π × 10 = 50π inches cubed
The amount of soup the can will hold is;
50π inches cubed = 157.08 inches cubed
To evaluate 17 int (sin^2 (x) cos^3(x))
From Trig identity. Cos^2(x) + sin^2(x) =1. Cos^2(x) = 1 - sin^2 (x)
Cos^3(x) = cosx * (1 - sin^2 (x)) = cosx - cosxsin^2x
So we have 17 int (sin^2x(cosx - cosxsin^2x))
int (sin^2x(cosx)dx - int (sin^4xcosx)dx. ----------(1)
Let u = sinx then du = cosxdx
Substituting into (1) we have
int (u^2du) - int (u^4du)
u^3/3 - u^5/5
Substitute value for u we have
(sinx)^3/3 - (sinx)^5/5
Hence we have 17 [ sin^3x/3 - sin^5x/5]
