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svet-max [94.6K]
2 years ago
14

On February 1, the electricity meter reading for the Smith residence was 19,423 kilowatt hours. On March 1, the meter read 20,28

8 kilowatt hours. On April 1, the meter read 21,163 kilowatt hours. a. How many kilowatt hours of electricity did the Smiths use during February? b. How many kilowatt hours did they use during March?
Mathematics
1 answer:
Karolina [17]2 years ago
8 0
A. How many kilowatt hours of electricity did the Smiths use during February?

Kilowatt hours of electricity the Smiths used during February:
Meter read on March 1 - meter read on February 1 =
20,288 kilowatt hours - 19,423 kilowatt hours =
865 kilowatt hours
Answer: The Smiths used 865 kilowatt hours of electricity during February

b. How many kilowatt hours did they use during March?

Kilowatt hours of electricity the Smiths used during March:
Meter read on April 1 - meter read on March 1 =
21,163 kilowatt hours - 20,288 kilowatt hours =
875 kilowatt hours
Answer: The Smiths used 875 kilowatt hours of electricity during March
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Chester, the dog, loves to eat treats. He has eaten twice as many today as yesterday. He has eaten a total of 15 dog treats in b
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Answer:

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Step-by-step explanation:

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Required

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if BD is perpendicular to AC M angle DBE equals 2x - 1 + m angle CBE equals 5x - 42 find the value of x​
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<h2>Answer:</h2>

<h2>Step-by-step explanation:</h2>

I've drawn a graph in order to a better understanding of this problem. We know that:

BC is perpendicular to AC

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∠CBE = 5x - 42

Let's call the intersection of line BC and AC the point P, so:

∠P=90°

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∠PBC = 2x - 1 - (5x - 42)

∠PBC = 2x - 1 - 5x + 42

∠PBC = -3x + 41

The internal angles of any triangle add up to 180°. Hence for ΔBPC:

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90° - 3x + 41  + 5x - 42  = 180°

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