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timama [110]
2 years ago
5

A banquet hall is being set up for a reception. Each round table will have 6 chairs and each rectangular table will have 10 chai

rs. The arrangement of tables must accommodate at least 185 guests to be seated. The client reserving the banquet hall requests that there be no more than 15 rectangular tables and no fewer than 6 round tables. Additionally, the number of rectangular tables used must be at least one-third the number of round tables used. Let x represent the number of round tables and y represent the number of rectangular tables.
What constraints are placed on the variables in this situation?
Select each correct answer. (In picture)

Mathematics
1 answer:
olga_2 [115]2 years ago
8 0

Answer:

in picture

Step-by-step explanation:

— Round tables will have 6 chairs, rectangular tables will have 10 chairs, the total number of chairs must be at least 185: 6x +10y ≥ 185

— There be no more than 15 rectangular tables: y ≤ 15

— No fewer than 6 round tables: x ≥ 6

— Rectangular tables must be at least 1/3 the number of round tables: y ≥ (1/3)x ⇒ 3y ≥ x

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(a) 0.0833 or 8.33%

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Parts line one (n1) = 1,000 parts

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Parts line two (n2) = 2,000 parts

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a. Probability of a randomly selected part being defective:

P(d) = \frac{d_1+d_2}{n_1+n_2}=\frac{100+150}{1,000+2,000}\\P(d) =0.0833=8.33\%

The probability is 0.0833 or 8.33%

b. Probability of a part being produced by line one, given that it is defective:

P(1|d)=\frac{P(1\cap d)}{P(1\cap d)+P(2\cap d)}\\P(1|d)=\frac{\frac{100}{3,000} }{\frac{100}{3,000}+\frac{150}{3,000}}\\P(1|d)=0.4 = 40\%

The probability is 0.40 or 40%.

5 0
1 year ago
Faelyn grouped the terms and factored the GCF out of the groups of the polynomial 6x4 – 8x2 + 3x2 + 4. Her work is shown.
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It is hard to say how Faelyn's work shows the polynomial is prime, but it is.

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Answer:

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