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Zigmanuir [339]
1 year ago
11

Find the area of quadrilateral ABCD. Round the area to the nearest whole number, if necessary. A(-5, 4) 4 B(0, 3) 2. F(-2, 1) -2

2. 6 x -2 24 E(2, -3) D( 45) 6 X The area is X x square units​
Mathematics
1 answer:
valentina_108 [34]1 year ago
5 0

Answer:26

Step-by-step explanation:

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As part of a company incentive, each sales person that sells over \$40{,}000$40,000dollar sign, 40, comma, 000 in merchandise th
worty [1.4K]

Answer:

$58,600

Step-by-step explanation:

Data provided in the question:

Commission on Sales upto and including $40,000 = 5%

Commission on Sales above $40,000 = 10%

Total commission = $3,860

Now,

For sales of $40,000

maximum commission = 5% of $40,000

= $2,000

Since the commission received is greater than $2,000

Therefore,

The value of s is greater than $40,000

Thus

Amount qualifying for 10% commission = s - $40,000

therefore,

Total commission = $2,000 + 10% of (s - $40,000)

or

$3,860 =  $2,000 + 0.10 × (s - $40,000)

or

$1,860 = 0.10 × (s - $40,000)

or

s - $40,000 = $18,600

or

s = $18,600 + $40,000

or

s = $58,600

4 0
1 year ago
Read 2 more answers
Explain how you can determine the number of real number solutions of a system of equations in which one equation is linear and t
Assoli18 [71]

Answer:

To determine the number of real number solutions of as system of equations in which one equation is linear and the other is quadratic

1) Given that there are two variables, x and y as an example, we make y the subject of the equation of the linear equation and substitute the the expression for y in x into the quadratic equation

We simplify and check the number of real roots with the quadratic formula, x = \dfrac{-b\pm \sqrt{b^{2}-4\cdot a\cdot c}}{2\cdot a} for quadratic equations  the form 0 = a·x² - b·x + c

Where b² > 4·a·c there are two possible solutions and when b² = 4·a·c equation there is only one solution.

Step-by-step explanation:

3 0
1 year ago
F (7-3)2 x 7x+4 = 77, find the value of x.
bearhunter [10]

Answer: If I am correct the value of x might be f=0

Step-by-step explanation:

5 0
1 year ago
Geometry: Line QS bisects angle PQR. Solve for x and find the measure of angle PQR.
Kazeer [188]

It is given in the question that,

Line QS bisects angle PQR. Solve for x and find the measure of angle PQR.

And

m \angle PQS = 2x+1
\\
m \angle RQS = 4x-15

Since QS bisects angle PQR, therefore

m \angle PQS = m \angle RQS

Substituting the values, we will get

2x+1=4x-15
\\
1+15 = 4x-2x
\\
2x = 16
\\
x = 8

6 0
1 year ago
Read 2 more answers
The line 3y+x=25 is a normal to the curve y=x2-5x+k.find the value of constant k.
ladessa [460]

Answer:

k = 11.

Step-by-step explanation:

y = x^2 - 5x + k

dy/dx = 2x - 5 = the slope of the tangent to the curve

The slope of the normal = -1/(2x - 5)

The line  3y + x =25 is normal to the curve so finding its slope:

3y = 25 - x

y = -1/3 x + 25/3 <------- Slope is -1/3

So at the point of intersection with the curve, if the line is normal to the curve:

-1/3 = -1 / (2x - 5)

2x - 5 = 3  giving x = 4.

Substituting for x in y = x^2 - 5x + k:

When x = 4, y =  (4)^2 - 5*4 + k  

y = 16 - 20 + k

so y = k - 4.

From the equation y = -1/3 x + 25/3,  at x = 4

y = (-1/3)*4 + 25/3 = 21/3 = 7.

So y = k - 4 = 7

k = 7 + 4 = 11.

6 0
2 years ago
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