Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro
2 answers:
The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now,
We know that the sum of probability of an event and its complement is 1.
So,
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.
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Answer:
From the frequency table, let's calculate the row total.
Row total for phone call = 19 + 9 = 28
Row total for no phone call = 8 +6 = 14
To calculate their respective row relative frequencies, let's use:
Row relative freq =
Now, the two-way frequency table will be computed as:
For phone call:
Desirable behavior = ≈0.69
Undesirable behaviour = ≈0.32
No phone call:
Desirable behaviour = ≈ 0.57
Undesirable behaviour = ≈ 0.43
The complete two-way table is attached.
