He can divide by 2,3,4,6,8,12,16,24,32, and 48 but
Answer:
3 3/8
Step-by-step explanation:
y×(2/3)=2.25 (the same as 2 1/4)
÷2/3. ÷2/3
y=3.375
3 3=8 gallons
more of break down:
y×2/3=9/4
÷2/3 or ×3/2
y= 9. 3. 27
--- × ---- = ----- = 3 3/8
4. 2. 8
Answer: you can use 260 min, 60 min at a fixed price ($20) and extra 200.
Step-by-step explanation:
C(x) = 20 + 0.20(x − 60)
C(x) ≤ 60
20 + 0.20(x − 60) ≤ 60
0.20(x − 60) ≤ 60 - 20
0.20x - 12 ≤ 40
0.20x ≤ 40 + 12
0.20x ≤ 52
x ≤ 52/0.2
x ≤ 260
This way, you can use 260 min, 60 min at a fixed price ($20) and extra 200.
<h2>
Therefore he took 40 gram of
type solution and 10 gram of
type solution.</h2>
Step-by-step explanation:
Given that , A pharmacist 13% alcohol solution another 18% alcohol solution .
Let he took x gram solution of
type solution
and he took (50-x) gram of
type solution.
Total amount of alcohol =
gram
Total amount of solution = 50 gram
According to problem
⇔![\frac{ [x\times\frac{13}{100}] +[(50 -x) \times\frac{18}{100} ]}{50}= \frac{14}{100}](https://tex.z-dn.net/?f=%5Cfrac%7B%20%5Bx%5Ctimes%5Cfrac%7B13%7D%7B100%7D%5D%20%2B%5B%2850%20-x%29%20%5Ctimes%5Cfrac%7B18%7D%7B100%7D%20%5D%7D%7B50%7D%3D%20%5Cfrac%7B14%7D%7B100%7D)
⇔
⇔- 5x= 700 - 900
⇔5x = 200
⇔x = 40 gram
Therefore he took 40 gram of
type solution and (50 -40)gram = 10 gram of
type solution.
A. (−3, 3)
<span>3x – 4y = 21
</span>3(-3) - 4(3) = 21
-21 = 21 >>>>> not equal
B. (−1, −6)
<span>3(-1) - 4(-6) = 21
</span>21 = 21 >>>>>>>>>>Equal
C. (7, 0)
<span>3(7) - 4(0) = 21
</span>21 = 21>>>>>>>>>>equal
D. (11, 3)
<span>3(11) - 4(3) = 21
</span>21 = 21 >>>>>>>>>equal